Let ‘s’ be the son’s age 12 years ago.
Let ‘f’ be the father’s current age.
4 years ago, the son was:
s-4
So, his father is currently:
3(s-4)
=
3s-12
Therefore:
f = 3s-12
In twelve years, the son will be:
s+12
And the father will be:
f+12
This can also be written as:
3s-12+12 as the fathers younger age would be f = 3s+12
=
3s
So, we know that s+12 is half the fathers current age, meaning the father is currently 2(s+12) which is equivalent to 2s+24. Also, we know that the father is currently 3 times the sons age 12 years ago, so 3s (proven by the calculations we made above). Therefore, 2s+24=3s which means 24=s. We can then substitute this, and we will receive 24+12 = 36
Son’s current age: 36
We then substitute the son’s age 12 years ago into 2s+24 to give us the father’s age.
2(24)+24 = 72
Father’s current age: 72
9000mm
because there is ten mm in one cm
Answer:
x≤−11
Step-by-step explanation:
−99≥18x−9x
−99≥9x
−
9
99
≥x
−11≥x
x≤−11
Answer: A
You’re basically adding m - 2 nine times
So it’s 9m - 18
Or 9m - 9(2)
Answer:
(2, 3)
Step-by-step explanation:
2x + 5y = 19
5y = -2x + 19
y = 
P(abscissa, ordinate)
P(x, 1.5x)
P(2, 3)
3 = 15/5
3 = 3
