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Drupady [299]
2 years ago
15

If you have 2 linear equations and you want to find where they have the same x- and y- value on a graph you look for the

Mathematics
1 answer:
marin [14]2 years ago
4 0

Answer:

Intersection of the two lines.

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System of equations <br><br> -8x + 4y = 24<br> -7x + 7y = 28<br><br> X= ___<br> Y=___
lilavasa [31]

Answer:

You would end up with X= -2, y= 2

And they would intersect at point (-2,2) on a graph :)

8 0
3 years ago
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How many students did Rebecca observe when she collected her data?
Elis [28]
We need the question and answer choices for us to answer
6 0
3 years ago
a suit cost $95 Barry has a discount coupon for 10% off and the city has a 4.5 percent sales tax what is the final cost of the s
SIZIF [17.4K]
SO the suit cost $95 and it has a discount of 10%
so 95*10/100=9.5
so 10% of 95 is 9.5
subtract 9.5 from 95 and that equals 85.5
then you have to add 4.5 percent sales tax
so 85.5+ 4.5%= 89.347
So the final cost would be $89.34
3 0
4 years ago
HELP! WILL AWARD BRAINLIEST TO WHOEVER ANSWERS BOTH PARTS CORRECTLY!!
rewona [7]

check the picture below.

now, we're assuming the trapezoid is an isosceles trapezoid, namely AD = BC, and therefore the triangles are twins.

incidentally, b is the height of the trapezoid and likewise is also the altitude or height of the concrete triangle.

so we can simply get the area o the trapezoid, notice the bottom base is a+185+a, and then get the area of the concrete triangle and subtract the triangle from the trapezoid, what's leftover is just the vegetation area.

\bf \begin{cases} a=283\cdot cos(80^o)\\ a\approx 49.14\\ --------\\ b=283\cdot sin(80^o)\\ b\approx 278.70 \end{cases}\\\\ -------------------------------\\\\ \textit{area of a trapezoid}\\\\ A=\cfrac{h(x+y)}{2}~~ \begin{cases} x,y=\stackrel{bases}{parallel~sides}\\ h=height\\ ----------\\ x=185\\ y\approx \stackrel{a+185+a}{283.28}\\ h\approx\stackrel{b}{278.70} \end{cases} \\\\\\ A=\cfrac{278.70(185+283.28)}{2}\implies A\approx 65254.818

so that's the area of the trapezoid, now let's get the area of the triangle.

\bf \stackrel{triangle}{\cfrac{1}{2}(185)(b)}\implies \cfrac{1}{2}(185)(278.70)\qquad \approx 25779.80\\\\ -------------------------------\\\\ \stackrel{\textit{area for vegetation}}{\stackrel{\textit{area of trapezoid}}{65254.818}~~-~~\stackrel{\textit{area of triangle}}{25779.80}}\implies 39475.018

since we know 36 yd² cost 12 bucks, then how much will it be for 39475.018 yd²?

\bf \begin{array}{ccll} yd^2&\$\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 36&12\\ 39475.018&x \end{array}\implies \cfrac{36}{39475.018}=\cfrac{12}{x}\implies x=\cfrac{39475.018\cdot 12}{36} \\\\\\ x\approx 13158.339\overline{3}

3 0
3 years ago
Please help, solve for x. Due today and all I’ve gotten are links :(
Nookie1986 [14]

Answer:

I think it might be 0 im not to sure.

6 0
3 years ago
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