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emmasim [6.3K]
3 years ago
10

If a car traveling at the constant rate of 67x=y , how far will it have traveled in 8.4 hours ?

Mathematics
1 answer:
lukranit [14]3 years ago
3 0
Dedhamhdjdjjdjdjejrkrmdjxx
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If y varies inversely as x and y=7 when x=−4, find y when x=2.
olga2289 [7]

Answer:

Explanation:

The statement is expressed as

y

∝

1

x

inverse means

1

variable

To convert to an equation introduce k, the constant of variation.

y

=

k

×

1

x

⇒

y

=

k

x

To find k use the given condition that y = 8 when x = 4

8

=

k

4

⇒

k

=

4

×

8

=

32

⇒

equation is

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2

2

y

=

32

x

2

2

∣

∣

∣

−−−−−−−−−−−−

x

=

16

→

y

=

32

16

⇒

y

=

2

when

x

=

16

5 0
3 years ago
PLEASE HELP ANYONE HELP ?!!!!!!!!!!!!!!!)))):::::
stealth61 [152]

Answer:

3x

Step-by-step explanation:

givens: x=4

now try your options:

3(4)+3=15

12+3=15

15=15

The first option is correct, therefore the answer is 3x

3 0
3 years ago
Read 2 more answers
A BASKETBALL PLAYER MAKES A BASKET THROUGH A TEN FOOT HIGH BASKET FROM 20 FEET AWAY. IF THE SHOOTER RELEASES THE BALL FROM 8 FEE
mixas84 [53]

Answer:

The vertical velocity of the ball when released = 10.81 m/s

The vertical velocity of the ball in the basket = 8.81 m/s

Step-by-step explanation:

The given parameters are;

The height of the basket = 10 feet

The horizontal location of the shooter from the basket = 20 feet

The height from which the shooter releases the ball = 8 feet

The horizontal velocity of the ball = 10 ft/s

Therefore, we have;

Time, t = Horizontal distance/(Horizontal velocity)

t = 20/10 = 2 seconds

The vertical velocity is given as follows;

s = u·t - 1/2·g·t²

Where;

u = The vertical velocity

s = The height above the initial height from which the ball is released

s = y - y₀

Where;

y = The final height of the ball in the calculation = The height of the basket = 10 foot

y₀ = The initial height from which the ball is released = 8 feet

∴ s = 10 - 8 = 2 feet

g = The acceleration due to gravity = 9.81 m/s²

Substituting gives;

2 = u × 2 - 1/2 × 9.81× 2²

u = (2 + 1/2 × 9.81× 2²)/2 = 10.81 m/s

The vertical velocity of the ball when released = 10.81 m/s.

The vertical velocity of the ball in the basket is given by the following relation;

v² = u² - 2·g·s

v² = 10.81² - 2×9.81×2 = 77.6161

v = √(77.6161) = 8.81 m/s

The vertical velocity of the ball in the basket = 8.81 m/s

7 0
2 years ago
Please awnser this asap​
Illusion [34]

Answer:

Base area = 25.2 in^2

Step-by-step explanation:

Base area = 63/2.5 = 25.2 in^2

8 0
2 years ago
In ΔSTU, the measure of ∠U=90°, the measure of ∠T=32°, and US = 5.8 feet. Find the length of ST to the nearest tenth of a foot.
murzikaleks [220]

Answer:

10.9451≈10.9 feet

Step-by-step explanation:

sinT= hypotenuse/ opposite = x/5.8

sin32= x/5.8

x*sin 32=5.8

x=5.8/sin 32= <u>10.9451≈10.9 feet</u>

8 0
2 years ago
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