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Leona [35]
3 years ago
11

Which of the following is characteristics of non-metals?

Chemistry
1 answer:
valentinak56 [21]3 years ago
4 0

Answer:

D. They tend to gain electrons in chemical reactions

Explanation:

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Is 2 KNO₃ + H₂CO₃ → K₂CO₃ + 4 HNO₃ a balanced equation
krok68 [10]

Hey there!

The elements in this equation are K, N, O, H, and C.

Let's count how many of each are on each side to see if it is balanced.

K: 2 on the left, 2 on the right.

<em>N: 2 on the left, 4 on the right. </em>

<em>O: 9 on the left, 6 on the right. </em>

<em>H: 2 on the left, 4 on the right. </em>

C: 1 on the left, 1 on the right.

Notice that there are different amounts of N, O, and H on the left side and the right side.

This means that the equation is not balanced.

Hope this helps!

6 0
3 years ago
Match the correct simple with the correct elements of safety
grigory [225]

<u>c.</u> 12. preparing data tables and gathering safety equipment

<u>b.</u> 13. reading all instructions before beginning a science lab

<u>a.</u> 14. recognizing what a picture of a hand means

<u>e.</u> 15. wiping your work area with a wet paper towel

<u>d.</u> 16. wearing goggles and an apron

3 0
3 years ago
How many mL of a stock solution of 2.00 M KNO3 are needed to prepare 100.0 mL of 0.15M KNO3? with work plz
Tatiana [17]
Using the law of dilution :

Mi x Vi =  Mf x Vf

2.00 x Vi = 0.15 x 100.0

2.00 x Vi = 15

Vi = 15 / 2.00

Vi = 7.5 mL

hope this helps!


3 0
3 years ago
A public School district furnishes pencils to its elementary school. The pencils the secretary orders from the district warehous
const2013 [10]

Answer:

The minimum number of boxes of pencils to be ordered is 630 boxes.

Explanation:

Since a pupil uses averagely 9.3 pencils

and a box contains 12 pencils,

the school enrollment is also 812

school's enrollment x average use of pencil per student

__________________________________________

            number of pencils in a box

812 x 9.3 = 7551.6

7551.6 /12 = 629.3

Having a total number of 630 boxes of pencils to be ordered.

3 0
3 years ago
Cho 4g CuO vào dung dịch axit clohidric 10% thì phản ứng vừa đủ.
Sholpan [36]

Answer:

Explanation:

a. CuO+ 2HCl⇒CuCl2+ H2O

b. n_{CuO}= \frac{4}{80}= 0,05 (mol)

⇒n_{CuCl2}= n_{CuO}=0,05 mol

⇒m_{CuCl2}= 0,05×135=6,75 (g)

c. n_{HCl}=2× n_{CuO}=0,1 (mol)

⇒m_{HCl}= 0,1×36,5= 3,65 (g)

⇒m_{dd HCl}= \frac{m_{HCl}}{10}×100=36,5 (g)

⇒ Nồng độ phần trăm dd sau phản ứng= Nồng độ % dd CuCl2=\frac{m_{CuCl2} }{m_{dd HCl+ m_{CuO} } }×100=\frac{6,75}{36,5+4} ×100≈ 16,67%

8 0
3 years ago
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