First you need to calculate the number of moles of aluminium and copper chloride.
number of moles = mass / molecular weight
moles of Al = 512 / 27 = 19 moles
moles of CuCl = 1147 / 99 = 11.6 moles
From the reaction you see that:
if 2 moles of Al will react with 3 moles of CuCl
then 19 moles of Al will react with X moles of CuCl
X = (19 × 3) / 2 = 28.5 moles of CuCl, way more that 11.6 moles of CuCl wich is the quantity you have. So the copper chloride is the limiting reagent.
Answer:- 12.7%
Solution:- It says, ammonium phosphate is 60.9%. It means if we assume 100 g of the sample then there is 60.9 g ammonium phosphate in it.
Formula of ammonium phosphate is 
and it's molecular weight is 149 grams per mol. There is only one P in the formula and so the mass of P in 149 g of ammonium phosphate is 31 g(atomic mass of P).
Now, we could use the proportions to find out the mass percentage of P in the sample.
31 g P is present in 149 g of ammonium phosphate, how many grams of P would be present in 60.9 g of ammonium phosphate. Let's set the proportions as:
This 12.7 g of phosphorous is present in 100 g of the sample means there is 12.7% phosphorous in the sample.
There are 6.022*10^23 molecules in 1 mole of carbon
So how many will moles will be 7.87*20^7?
Let the required number of moles be ‘x’.
1 mole ———6.022*10^23
x moles———7.87*10^7
(Cross multiplication)
x=7.87*10^7/6.022*10^23
Therefore x=1.3*10^-16
Sds stands for safety data sheet which contains all different sorts of chemicals and hazardous substances. B liquid
