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Anettt [7]
3 years ago
12

What specifically determines how much energy is available in a molecular

Chemistry
1 answer:
HACTEHA [7]3 years ago
4 0

C  The number and types of bonds within the molecule.

Explanation:

In a molecule, the number and types of bonds present determines the amount of available energy therein.

When bonds are broken or formed, energy is usually released.

  • Elements combine with one another in order to attain stability in this state.
  • Through this process, they form bonds by attraction.
  • Where atoms exchange their valence electrons by losing or gaining it, electrovalent bonds form.
  • In covalent molecules, electrons are usually shared between atoms.
  • An attraction result from this type of interaction.
  • The bond formed stores energy in the process.
  • When bonds are broken, energy is usually released. The energy accrues when the bond was being formed.
  • In molecules, we have covalent bond.

Learn more:

Bond brainly.com/question/7213980

Covalent bonds brainly.com/question/5258547

#learnwithBrainly

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Correct answer please i need it before 12:07
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Answer:

xenon

Explanation:

Xenon is a non-metal, odorless gas, consist of single atoms, colorless, and 8 valence electrons out of everything else on this list.

6 0
2 years ago
Please someone help mee
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Answer:

13.9kj/mol

Explanation:

h = 891 -(393.5 +2*241.8)=1768.1=13.9kj/mol

8 0
3 years ago
Predict the following chemical formula for a compound between lithium and oxygen
zhuklara [117]
Li2O.. Because Li is +1 and O2 is -2
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What is the definition of sound energy
oksian1 [2.3K]

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4 0
3 years ago
How many mL of 0.715 M HCl is required to neutralize 1.25 grams of sodium carbonate? (producing carbonic acid)
jonny [76]

Answer:

34 mL

Explanation:

We'll begin by calculating the number of mole in 1.25 g of sodium carbonate, Na₂CO₃. This can be obtained as follow:

Mass of Na₂CO₃ = 1.25 g

Molar mass of Na₂CO₃ = (23×2) + 12 + (16×3)

= 46 + 12 + 48

= 106 g/mol

Mole of Na₂CO₃ =?

Mole = mass /molar mass

Mole of Na₂CO₃ = 1.25 / 106

Mole of Na₂CO₃ = 0.012 mole

Next, we shall determine the number of mole HCl needed to react with 0.012 mole of Na₂CO₃.

The equation for the reaction is given below:

Na₂CO₃ + 2HCl —> H₂CO₃ + 2NaCl

From the balanced equation above,

1 mole of Na₂CO₃ reacted with 2 moles of HCl.

Therefore, 0.012 mole of Na₂CO₃ will react with = 0.012 × 2 = 0.024 mole of HCl.

Next, we shall determine the volume of HCl required for the reaction. This is illustrated:

Mole of HCl = 0.024 mole

Molarity of HCl = 0.715 M

Volume of HCl =?

Molarity = mole /Volume

0.715 = 0.024 / volume of HCl

Cross multiply

0.715 × volume of HCl = 0.024

Divide both side by 0.715

Volume of HCl = 0.024 / 0.715

Volume of HCl = 0.034 L

Finally, we shall convert 0.034 L to mL

This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.034 L = 0.034 L × 1000 mL / 1 L

0.034 L = 34 mL

Therefore, 34 mL of HCl is needed for the reaction.

6 0
3 years ago
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