Question

About limit function, solve this

Answer 1

$\lim \limits_{x \to2} \frac{ {x}^{2} - 4 }{x - 2} \\ = \lim \limits_{x \to2} \frac{ {(x)}^{2} - {(2)}^{2} }{x - 2} \\ = \lim \limits_{x \to2} \frac{ ( x- 2)(x + 2) }{x - 2} \\ = \lim \limits_{x \to2} ( x+ 2) \\ = 2 + 2 \\ = 4$

Answer:

4

Hope you could understand.

If you have any query, feel free to ask.

Answer 2

Answer:

The limit of the function as x approaches 2 is 4.

Step-by-step explanation:

This function just simplifies to $x+2$:

$\frac{x^2-4}{x-2}\\\\\frac{(x+2)(x-2)}{x-2}\\\\x+2$

That leaves us with this:

​$\lim_{x\to2}x+2$

This is a simple linear function that can be evaluated at $x=2$:

$f(x)=x+2\\f(2)=2+2\\f(2)=4$

The values also exist on either side of this point.

$f(1.999)=3.999\\f(2.001)=4.001$