Answer:113
Step-by-step explanation:
I guessed
Just in case you did not see it on the other question.
5 months
Month 1: $375 Mini $3.15 Murk
Month 2: $375 Mini $3.15 Murk
Month 3: $165.58 Mini $209.42 Murk
Month 4: $375 Murk
Month 5: $87.36 Murk
Answer:
x = 10.3 in
Step-by-step explanation:
To find the value of a, use the area formula for a triangle. The formula is A = 1/2 *b*h. Here b = x and h= x. The formula becomes A = 1/2 *x². Substitute A = 53 and solve for x by using inverse operations.
A = 1/2x²
53 = 1/2x²
106 = x²
√106 = x
10.3 = x
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of 660, hence
.
- The standard deviation is of 90, hence
.
- A sample of 100 is taken, hence
.
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

By the Central Limit Theorem



has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213
Answer:
$5659.11
Step-by-step explanation:
We are given;
- Time of loan maturity is 5 years
- Rate of compound interest is 7% compounded quarterly
- Principal amount of the car is $4000
We are required to determine the total amount he paid at the end of 5 years..
The concept being tested is compound interest;
We are going to use the compound interest formula;
Amount = P(1+r/100)^n
Where P is the the principal amount
r is the rate of interest
n is the interest periods
In this case;
n = (5 × 4) = 20
r = 7 ÷ 4 = 1.75 ( as the money was compounded quarterly)
Thus;
Amount =$ 4000 ( 1 + 1.75)^20
= $4000 (1.0175)^20
= $5659.11
Therefore, the money that Joe will have paid at the end of 5 years is $5659.11