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3 years ago

How is a common denominator in a common multiple alike

Mathematics

2 answers:

aleksley [76]3 years ago

7 0

They both have the same number and relat togethor

Tasya [4]3 years ago

3 0

Whatever you do to the denominator you do to the numerator.

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Which graph represents the solution set to the system of inequalities?<br><br> y≤1/4 x−2, y≥−5/4 x+2

jenyasd209 [6]

The first one. <_ means below and >_ means above. <_ and >_ means solid line < and > mean dotted line. i’m learning this in math right now

5 0

3 years ago

Solve the equation. Round to the nearest hundredth. Show work.

Burka [1]

Answer:

$x=-0.75$

Step-by-step explanation:

The given equation is

$4^{-5x-7}=6^{2x-1}$

We take logarithm of both sides to base 10.

$\log(4^{-5x-7})=\log(6^{2x-1})$

$(-5x-7)\log(4)=(2x-1)\log(6)$

We expand the brackets to get;

$-5x\log(4)-7\log(4)=2x\log(6)-\log(6)$

Group similar terms;

$-7\log(4)+\log(6)=2x\log(6)+5x\log(4)$

$-7\log(4)+\log(6)=(2\log(6)+5\log(4))x$

$\frac{-7\log(4)+\log(6)}{(2\log(6)+5\log(4))}=x$

$x=-0.752478$

To the nearest hundredth.

$x=-0.75$

3 0

3 years ago

And a wildlife preserve 46 ducks are captured tagged and then released. Later to her ducks are examined in four of the 200 ducks

docker41 [41]

Answer:

2300

Step-by-step explanation:

We are given that

Out of 200 , four ducks are tagged.

We have to find the number of ducks in the preserve if 46 ducks are tagged.

Let x be the number of ducks in the preserve.

If number of tagged ducks increases then number of preserved ducks also increases.It is in direct proportion.

According to question

$\frac{x}{46}=\frac{200}{4}$

$x=\frac{200\times 46}{4}$

$x=50\times 46$

x=2300

4 0

3 years ago

Conjectures and Postulates are accepted as true without formally proving they are true.

zlopas [31]

The answer is false, it is only true for postulates, not conjectures.

7 0

3 years ago

Read 2 more answers

beginning at sea level a scuba diver dove 1 2/3 feet into the water , and then dove an additional 3 2/5 feet at what elevation i

skad [1K]

The given details are illustrations of addition and subtractions of fractions. The scuba driver is at an elevation of $-5\frac{1}{15}$ ft below the sea level.

Given that:

$n_1 = 1\frac 23$ --- the first dive

$n_2 = 3\frac 25$ ---- the additional dive

From the question, we understand that the diver starts at the sea level.

This is represented with 0ft.

So, the diver's elevation (d) is calculated as follows:

$d = 0 - n_1 - n_2$ --- we use subtraction because the diver is below the sea level

So, we have:

$d = 0 - 1\frac 23 - 3\frac 25$

$d = - 1\frac 23 - 3\frac 25$

Convert fractions

$d = - \frac 53 - \frac{17}5$

Take LCM

$d = \frac{-5 \times 5 - 17 \times 3}{15}$

$d = \frac{-76}{15}$

Reduce fraction

$d = -5\frac{1}{15}$

The above value means that the diver's elevation is at $-5\frac{1}{15}$ ft below the sea level.