Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
The first 6 is equal to 6,000. The second 6 is equal to 600. 6,000 is 10 times greater than 600.
Hope this Helps!
Answer:
A
Step-by-step explanation:
this is true due to the ratio of a 30-60-90 triangle, which is 1-2-sqrt(3). The 12 corresponds to the sqrt(3), which means that the 1 corresponds to 4sqrt3 and the 2 to 8sqrt3.
:)
Factoring – Using the Distributive Property. A factor is a number that can be divided into another number evenly. For example, the factors of 6 are 1, 2, 3, and 6. ... It means that a number outside the parentheses of an addition problem can be multiplied by each number inside the parentheses.
First problem:
cos (theta)=1
Using the inverse cosine function, you get theta = 0.
Now we find tan 0 = 0
cot(theta) = 1/tan(theta) = 1/0
Division by zero is undefined, so the answer is d. undefined
Second problem:
cos (theta)=1
Use the inverse cosine function.
theta = 0°
Answer: c. 0°
