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Alona [7]
3 years ago
8

Find the sum of ∠BCD and ∠SBT in terms of x.

Mathematics
2 answers:
AleksAgata [21]3 years ago
4 0
Let's\ \angle TCB=y^o\\\\\angle SBT\ is\ the\ exterior\ angle\ of\ \Delta TCB,\ therefore\ |\angle SBT|=x^o+y^o.\\\\|\angle\ BCD|\ +\ y^o=180^o-angles\ on\ one\ side\ of\ a\ straight\ line\\\\|\angle BCD|=180^o-y^o\\\\therefor\\\\\angle SBT+\angle BCD=x^o+y^o+180^o-y^o=x^o+180^o\\\\\boxed{Answer:\angle SBT+\angle BCD=x^o+180^o}
skad [1K]3 years ago
4 0
Hello,

If we draw the parallele of AB passing through B
<span>∠SBT=x+x=2x
</span><span>∠BCT=x ==></span><span>∠BCD=180°-x
</span>
∠SBT+<span>∠BCD=2x+180°-x=180°+x

</span>
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