Answer:
A/C
Step-by-step explanation:
Since the sum of the angles in a triangle equals 180°, and angle C is 90°.
That means angles A and B add up to 90°, that is, they are complementary angles. Therefore the cosine of B equals the sine of A.
We saw on the last page that sin A was the opposite side over the hypotenuse, that is, a/c. Hence, cos B equals a/c.
Your welcome! :)
The equation of the line is y - 3 = 5(x - 8) ⇒ c
Step-by-step explanation:
The point-slope form of the linear equation is
, where:
- m is the slope of the line
is a point on the line
∵ The line passes through point (8 , 3)
∴
= 8 and
= 3
∵ The slope of the line is 5
∴ m = 5
- Substitute these values in the form of the equation below
∵ ![y-y_{1}=m(x-x_{1})](https://tex.z-dn.net/?f=y-y_%7B1%7D%3Dm%28x-x_%7B1%7D%29)
∴ y - 3 = 5(x - 8)
The equation of the line is y - 3 = 5(x - 8)
Learn more:
You can learn more about the linear equations in brainly.com/question/1284310
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Answer:
180.55 in².
Step-by-step explanation:
Data obtained from the question include the following:
Height (h) = 9 in.
Diameter (d) = 5 in
Pi (π) = 3.14
Area of the label =..?
Next, we shall determine the radius.
Diameter (d) = 5 in
Radius (r) =.. ?
Radius (r) = Diameter (d) /2
r = d/2
r = 5/2
r = 2.5 in.
Next, we shall determine the area of the label that needs to be printed to go around the new container by calculating the surface area of the cylinder.
This is illustrated below:
Height (h) = 9 in.
Pi (π) = 3.14
Radius (r) = 2.5 in.
Surface Area (SA) =.?
SA = 2πrh + 2πr²
SA = (2×3.14×2.5×9) + (2×3.14×2.5²)
SA = 141.3 + 39.25
SA = 180.55 in²
The surface area of the cylinder is 180.55 in².
Therefore, the area of the label that needs to be printed to go around the new container is 180.55 in².
4s + 5 = 19
First, subtract 5 from both sides. / Your problem should look like: 4s = 19 - 5.
Second, simplify 19 - 5 to 14. / Your problem should look like: 4s = 14.
Third, divide both sides by 4. / Your problem should look like: s =
![\frac{14}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B14%7D%7B4%7D%20)
.
Fourth, simplify
![\frac{14}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B14%7D%7B4%7D%20)
to
![\frac{7}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B7%7D%7B2%7D%20)
. / Your problem should look like: s =
![\frac{7}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B7%7D%7B2%7D%20)
which is the answer.