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elena-14-01-66 [18.8K]

4 years ago

12

Si l'on écrit sous forme décimale le nombre 1000000000**33-33 qu'elle est la somme des chiffres de ce nombre

1 answer:

PtichkaEL [24]4 years ago

3 0

Who is going to get it while it's in whatever language that is

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How many arrangements of three letter can be formed from the letters of the word MATH if anyletter will not be used more than on

Mariulka [41]

Combinations = n! / (n - r)! r!

$C\text{ = }\frac{n!}{(n-r)!\text{ r!}}\text{ }$

In this case:

n = 4

r = 3

Combinations = 4! /(4-3)! 3! = 24/(1)(6) = 24/6 = 4

Answer:

4 arrangements

7 0

1 year ago

Benjamin writes an expression for the sum of 1 cubed, 2 cubed, and 3 cubed -- What is the value of the expression? options---

saw5 [17]

Answer:

36

Step-by-step explanation:

1^3 + 2^3 + 3^3= 1+8+27

9+27= 36

7 0

3 years ago

Evaluate the function f(x) at the given numbers (correct to six decimal places). F(x) = x2 − 5x x2 − x − 20 , x = 5.5, 5.1, 5.05

exis [7]

we are given

$f(x)=\frac{x^2-5x}{x^2-x-20}$

Firstly, we will simplify it

$f(x)=\frac{x(x-5)}{(x-5)(x+4)}$

$f(x)=\frac{x}{(x+4)}$

At x=5.5:

we can plug x=5.5

$f(5.5)=\frac{5.5}{(5.5+4)}$

$f(5.5)=0.578947$

At x=5.1:

we can plug x=5.1

$f(5.1)=\frac{5.1}{(5.1+4)}$

$f(5.1)=0.56043956$

At x=5.05:

we can plug x=5.05

$f(5.05)=\frac{5.05}{(5.05+4)}$

$f(5.05)=0.558011$

At x=5.01:

we can plug x=5.01

$f(5.01)=\frac{5.01}{(5.01+4)}$

$f(5.01)=0.5560488$

At x=5.005:

we can plug x=5.005

$f(5.005)=\frac{5.005}{(5.005+4)}$

$f(5.005)=0.5558023$

At x=5.001:

we can plug x=5.001

$f(5.001)=\frac{5.001}{(5.001+4)}$

$f(5.001)=0.5556049$

At x=4.9:

we can plug x=4.9

$f(4.9)=\frac{4.9}{(4.9+4)}$

$f(4.9)=0.5505617$

At x=4.95:

we can plug x=4.95

$f(4.95)=\frac{4.95}{(4.95+4)}$

$f(4.95)=0.5530726$

At x=4.99:

we can plug x=4.99

$f(4.99)=\frac{4.99}{(4.99+4)}$

$f(4.99)=0.55506117$

At x=4.995:

we can plug x=4.995

$f(4.995)=\frac{4.995}{(4.995+4)}$

$f(4.995)=0.55503085$

At x=4.999:

we can plug x=4.999

$f(4.999)=\frac{4.999}{(4.999+4)}$

$f(4.999)=0.55550616$

7 0

4 years ago

Which of the following types of statement can be used to explain the steps of a proof? Choose all that apply. A. Postulate B. Th

slamgirl [31]

A postulate and a theorem :)

4 0

3 years ago

Read 2 more answers

What is (3.9 times 10 to the power of 2) times (2.3 times 20 to the power of 6)

Lady bird [3.3K]

(3.9*10^2)(2.3*20^6)
(3.9*100)(2.3*64000000)
(390)(147200000)
57408000000 <<< is your answer

5 0

3 years ago