Answer:
11x5 is 55
Step-by-step explanation:
Answer:
Heights of 29.5 and below could be a problem.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.
This means that 
There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus


Heights of 29.5 and below could be a problem.
45% of 76
45%=0.45
0.45*76
34.2
34.2 is about 34
so 34
Answer:
1/2
Step-by-step explanation:
We have to follow the order of operations. Since there are no parenthesis or exponents, we do multiplication first. to multiple fractions, we multiply the two numerators (top parts), which in this situation would get us 5*1=5. Then, we multiply the two denominators (bottom parts), which would get us 8*2=16. then we put the first result over the second, and we get 5/16. since the two denominators are the same, we don't need to change anything. we can just add the numerator, and get 8/16, which simplifies to 1/2.
Answer:
t ≥ 1.5
Step-by-step explanation:
Lets take time for practicing the piano to be t
The number of hours to practice per week should be at least 6 hours
This is written as t ≥ 6
She already practiced 3 hours this week, thus the remaining hours to practice should be
t ≥ 3
The minimum remaining hours to practice for the remaining 2 days should be
t=3
If these hours are evenly divided, then in a single day she should practice
for t ≥ 1.5