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agasfer [191]
3 years ago
10

Answer please thank ​

Mathematics
1 answer:
ollegr [7]3 years ago
3 0
The third one so C is the correct answer
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The circumference A of a circle varies directly with its radius. A circle with a radius of 4 has a circumference of about 25.1 i
horsena [70]

Answer:

25.1 in.2.

Step-by-step explanation:

8 0
3 years ago
Please help me me with this please actually help me please and thank you
Vsevolod [243]

Answer:

A. (-1, 3)

Step-by-step explanation:

To solve, find which point in the options are in the double shaded region (the region that is shaded the darkest which is the region above the point where the lines cross).

A. (-1, 3) is the correct answer because it falls in the correct region.

B. (-4, 1) is not the correct answer because it does not fall ABOVE both lines like the question says.

C. (0, 1) is not the correct answer because it falls in the 2nd darkest region.

6 0
2 years ago
Please help!!
fgiga [73]

The price of the small pots is $2.40 so you would have 2.4s ( multiply the number of small pots by the price)

She bought a total of 14 pots, so the number of large pots would be 14 - s ( subtract the number of small pots from the total )


Now you have:

L = 14-s

2.4s + 5.6(14-s) = 49.6


The answer is C.

7 0
3 years ago
Which of the following points is a solution to the system of linear inequalities
Sergeu [11.5K]
For it to be a solution, it has to satisfy both inequalities...

subbing in (-4,-1)

2x + y < -5                           -x + y > 0
2(-4) - 1 < - 5                      -(-4) - 1 > 0
-8 - 1 < -5                              4 - 1 > 0
-9 < -5.....true                        3 > 0....true

solution is (-4,-1)

3 0
3 years ago
Read 2 more answers
Multiply.
Crank
The main rules that we use here are :

i) \sqrt{a \cdot b}=  \sqrt{a} \cdot \sqrt{b} for nonnegative values a and b.

ii) \sqrt{a} \cdot  \sqrt{a} =a.


Thus, first 'decompose' the numbers in the radicals into prime factors:

4 \sqrt{3} \cdot 10 \cdot  \sqrt{2\cdot2\cdot3}\cdot  \sqrt{2\cdot 3}\cdot  \sqrt{2}..

By rule (i) we write:

4 \sqrt{3} \cdot 10 \cdot \sqrt{2}\cdot \sqrt{2}\cdot \sqrt{\cdot3}\cdot \sqrt{2} \cdot  \sqrt{3} \cdot \sqrt{2}.

We can collect these terms as follows:

40 \sqrt{3}\cdot (\sqrt{3}\cdot \sqrt{3}) \cdot (\sqrt{2}\cdot \sqrt{2}) \cdot( \sqrt{2} \cdot \sqrt{2}), and by rule (ii) we have:

40 \sqrt{3}\cdot 3 \cdot 2 \cdot2=40\cdot12\cdot \sqrt{3}=480 \sqrt{3}.


Answer: 480 \sqrt{3}.
8 0
4 years ago
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