Answer:
-1/5
Step-by-step explanation:
We know that a^b * a^c = a^(b+c)
(−5)^5(−5)^−6
(-5) ^(5+-6)
(-5)^-1
We know that a^-b = 1/a^b
1/(-5)^1
1/-5
-1/5
Step-by-step explanation:
1st expression
= px^4 + px
= px ( x³ + 1 )
= px ( x + 1) (x² - x + 1)
2nd expression
= qx³ - qx
= qx ( x² - 1 )
= qx ( x + 1) ( x - 1)
HCF = x ( x + 1)
Hope it will help :)❤
Answer:
A 1.9
Step-by-step explanation:
Nt = No e^(-kt)
Where Nt is the ending amount
No is the starting amount
k is the decay constant
and t is the time
We need to determine the half life
Nt/No = e ^ -kt
1/2 of the original amount is left for 1/2 life. The time is 40 years. We will calculate k
1/2 = e ^ -k * 40
Take the natural log of each side
ln(1/2) = ln (e ^ -k * 40)
ln (1/2) = -40k
-ln(2) = -40k
ln 2 = 40k
1/40 ln (2) = k
Now we can calculate now much is left after 160 years of a 30 g sample
Nt = 30 e^(- 1/40 ln(2) * 160)
= 30 e^(-4ln(2))
= 15/8
=1.875
Answer: b. $22.75
Step-by-step explanation:
Given : A large pizza with no toppings costs $14.00. A large pizza with 2 toppings costs $17.50.
Let x denotes the number of toppings and y be the cost of that pizza.
Then, 
, m= cost per topping and c= cost of pizza without any topping.
From the given information.
c= $14
Function of cost becomes = 
For x= 2 and y= 17.50, we have
tex]3.50=m(2)[/tex] [Subtract 14 from both sides]
[Divide both sides by 2]
For c= 14 and m =1.75 , our function becomes.
Now, for x= 5
Hence, the cost of a pizza with 5 toppings = $22.75
