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2 years ago

What’s the difference between 303 and 184

Mathematics

2 answers:

vazorg [7]2 years ago

5 0

Answer:

119

Step-by-step explanation:

forsale [732]2 years ago

3 0

Answer:

119

Step-by-step explanation:

Line up the Number

3 0 3

- 1 8 4

Subtract each column of digits, starting from the right and working left

If the digit being subtracted is larger than the digit above it, " Borrow" a digit from the next column to the left.

In the bold column, subtract the second digit from the first

3 0 3

- 1 8 4

The bottom number is larger than the upper number. Try to "Borrow" a digit from the left.

The top digit is not bigger than the bottom one. Try to "borrow a digit from the left.

3 0 3

- 1 8 4

Borrow 1 from 3. the remainder is 2

2 10

3 0 3

- 1 8 4

Add 1 ten to 0: 10+0=10

2 10

3 0 3

- 1 8 4

Borrow 1 from 10. The Remainder is 9

2 9 10

3 10 3

- 1 8 4

Add 1 ten to 3: 10 10+3=13

2 9 13

3 10 3

- 1 8 4

In the bold column, subtract the second digit from the first: 13-4=9

2 9 13

3 10 3

- 1 8 4

------------------------

In the bold column, subtract the second digit from the first: 9-8=1

2 9 13

3 10 3

- 1 8 4

------------------------

1 9

In the bold column, subtract the second digit from the first: 2-1=1

2 9 13

3 10 3

- 1 8 4

------------------------

1 1 9

= 119

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If k(x) = x^2 and p(x) = k(x) + n, what is the value of n?

kodGreya [7K]

Answer:

The value of n is -6

Step-by-step explanation:

If the function f(x) is translated k units up, then its image is g(x) = f(x) + k

If the function f(x) is translated k units down, then its image is g(x) = f(x) - k

The vertex form of the quadratic function is f(x) = a(x - h)² + k, where a is the coefficient of x² and (h, k) is the vertex

∵ k(x) = x²

→ Its graph is a parabola with vertex (0, 0)

∴ The vertex of the prabola which represents it is (0, 0)

∵ The given graph is the graph of p(x)

∵ Its vertex is (0, -6)

∴ h = 0 and k = -6

∵ a = 1

→ Substitute them in the form above

∴ p(x) = 1(x - 0)² + -6

∴ p(x) = x² - 6

→ Substitute x² by k(x)

∴ p(x) = k(x) - 6

∵ p(x) = k(x) + n

→ By comparing the two right sides

∴ n = -6

∴ The value of n is -6

Look at the attached figure for more understanding

The red parabola represents k(x)

The blue parabola represents p(x)

8 0

3 years ago

HELP ME FIND THE ANGLE<br><br><br><br><br> HELP ME FIND ANGLE A

romanna [79]

Answer:

32 degrees

Step-by-step explanation: So they tell you BE is congruent to BC so triangle BCE is isosceles. We know that angle C is 35 degrees and the triangle is isosceles so angle E is 35 degrees too. Now we do 180-(35+35) and that equals 110 so angle B is 110. And we know that angle EBC and FBA are supplementary angles so 180-110 is 70 degrees so angle FBA is 70 degrees and you can do the same thing with angle DFB and AFB so 180-102 degrees is 78 degrees and to find angle a you just do 180-(70+78) and that equals 32 degrees so angle A is 32 degrees. :)

4 0

3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$