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Kruka [31]
3 years ago
10

The ocean stores carbon from its interactions with the atmosphere, so the ocean serves as (a) _________ for the carbon cycle.

Chemistry
2 answers:
anyanavicka [17]3 years ago
7 0

\huge{\underline{ \pink{Answer}}}

\tt \bf \: carbon \:  \: sink

\tt \: The  \:  \:  ocean  \:  \: stores  \:  \: carbon \\ \tt  from \: \: its \:  \:  interactions \:  \:  with \:  \:  the \:  \:  atmosphere,   \\ \tt so \:  \:  the \:  \:  ocean \:  \:  serves  \:  \: as  \\ \tt (a)  \bf \: carbon \:  \: sink \:  \: for  \\ \tt the \:  \:  carbon  \:  \: cycle

.

Ilya [14]3 years ago
6 0

Answer:

<u><em></em></u>\boxed{Carbon~ Sink}

Explanation:

<em>Any reservoir, natural or otherwise, is called a carbon sink, that accumulates or stores some carbon.</em>

<em />

<em>Nowadays the 2 more important carbon sinks are </em><em>vegetation and the oceans.</em>

<em />

<em>We can also say that </em><em>atmosphere, soil, and forests are the world's largest carbon sinks. </em>

<em></em>

<em>Also, we can describe the carbon sink as anything that absorbs more carbon from the atmosphere than it releases.</em><em> In contrast, a carbon source is anything that releases more carbon into the atmosphere than it absorbs, e.g. the burning of fossil fuels or volcanic eruptions.</em>



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leva [86]

<u>Answer:</u> The density of the metal is 10.60 g/mL and the volume occupied by 86.0 grams is 8.11 mL

<u>Explanation:</u>

To calculate the density of unknown metal, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}       ......(1)

Volume of unknown metal = 19.8 mL

Mass of unknown metal = 210.0 g

Putting values in equation 1, we get:

\text{Density of unknown metal}=\frac{210.0g}{19.8mL}\\\\\text{Density of unknown metal}=10.60g/mL

The density of the metal remains the same.

Now, calculating the volume of unknown metal, using equation 1, we get:

Density of unknown metal = 11.45 /mL

Mass of unknown metal = 86.0 g

Putting values in above equation, we get:

10.60g/mL=\frac{86.0g}{\text{Volume of unknown metal}}\\\\\text{Volume of unknown metal}=8.11mL

Hence, the density of the metal is 10.60 g/mL and the volume occupied by 86.0 grams is 8.11 mL

5 0
4 years ago
Metal cations are atoms that have a positive charge. What type of bond is a metal cation likely to form? A. covalent bond B. dou
Lunna [17]

Answer:

D. ionic bond

Explanation:

Due to electron deficiency in a metal cation, they cannot form a covalent bond beacuse it means to share electrons. By contrast metal cation seek for electrons. In an ionic bond, one atom give electrons, while another atom recevie electron. Because of that, this is the better option to metal cations.

4 0
3 years ago
Water can only dissolve inorganic compounds
mote1985 [20]
Water can only dissolve inorganic compounds is false 


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4 years ago
Elements K and L have 12 and 17 protons respectively. If k has 24 neutrons and L has 36, in a tabular form identify the number o
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3 years ago
Co(g) effuses at a rate that is ______ times that of cl2(g) under the same conditions.
il63 [147K]

Answer is: the ratio of the effusion rate is 1.59 : 1.

1) rate of effusion of carbon monoxide gas = 1/√M(CO).  

rate of effusion of carbon monoxide gas = 1/√28.

rate of effusion of carbon monoxide gas = 0.189.  

2) rate of effusion of chlorine = 1/√M(Cl₂).  

rate of effusion of chlorine = 1/√70.9.  

rate of effusion of chlorine = 0.119.  

rate of effusion of carbon monoxide : rate of effusion of chlorine =

= 0.189 : 0.119 / ÷0.119.

rate of effusion of carbon monoxide : rate of effusion of chlorine = 1.59 : 1.

4 0
3 years ago
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