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Margarita [4]
3 years ago
8

Calculate the volume of a carbon monoxide when 22 grams of CO(g) exerts a pressure of 99.5 Kpa at 50 C.

Chemistry
1 answer:
WITCHER [35]3 years ago
7 0

Answer:

21.32 L

Explanation:

First, convert grams to moles using molar mass. C has a mass of 12 and O has a mass of 16. CO2 will therefore have a mass of 28 g/mol. Divide 22 by 28 to get about 0.79 moles. Convert C to Kelvin by adding 273; getting 323K. Then use the ideal gas law (PV=nRT) to solve for V (V=nRT/P). This gets you 21.32 L, hope this helps!

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The pressure on 150 mL of a gas is increased from 500 mm Hg to 700 mm Hg at constant temperature. What is the new volume of the
Ivanshal [37]

Answer:

Option A. 107 mL

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 150 mL

Initial pressure (P₁) = 500 mmHg

Final pressure (P₂) = 700 mmHg

Temperature = constant

Final volume (V₂) =?

The final volume of the gas can be obtained by using the Boyle's law equation as shown below:

P₁V₁ = P₂V₂

500 × 150 = 700 × V₂

75000 = 700 × V₂

Divide both side by 700

V₂ = 75000 / 700

V₂ = 107 mL

Therefore, the final volume of the gas is 107 mL.

4 0
3 years ago
A 0.223 mole sample of gas is held at 33.0 C and 2.00 atm, What's the volume of the gas? R = 0.0821 L atm / mol K answer soon il
Ghella [55]

Answer:

The volume of the gas is 2.80 L.

Explanation:

An ideal gas is a theoretical gas that is considered to be made up of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The Pressure (P) of a gas on the walls of the container that contains it, the Volume (V) it occupies, the Temperature (T) at which it is located and the amount of substance it contains (number of moles, n) are related from the equation known as Equation of State of Ideal Gases:

P*V = n*R*T

where R is the constant of ideal gases.

In this case:

  • P= 2 atm
  • V= ?
  • n=0.223 moles
  • R= 0.0821 \frac{L*atm}{mol*K}
  • T=33 °C= 306 °K (being O°C= 273°K)

Replacing:

2 atm* V= 0.223 moles*0.0821 \frac{L*atm}{mol*K}* 306 K

Solving:

V=\frac{0.223 moles*0.0821\frac{L*atm}{mol*K} * 306 K}{2 atm} \\

V= 2.80 L

<u><em>The volume of the gas is 2.80 L.</em></u>

7 0
3 years ago
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SCORPION-xisa [38]

Answer:

Firsthand association assigns energy throughout conduction. Radiation transpires when particles consume energy that progresses as a wave. The heat will run from the h2O to the ice continuously until the ice has absolutely melted so both elements have reached the same temperature.

Explanation:

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