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3 years ago

Co(g) effuses at a rate that is ______ times that of cl2(g) under the same conditions.

Chemistry

1 answer:

il63 [147K]3 years ago

4 0

Answer is: the ratio of the effusion rate is 1.59 : 1.

1) rate of effusion of carbon monoxide gas = 1/√M(CO).

rate of effusion of carbon monoxide gas = 1/√28.

rate of effusion of carbon monoxide gas = 0.189.

2) rate of effusion of chlorine = 1/√M(Cl₂).

rate of effusion of chlorine = 1/√70.9.

rate of effusion of chlorine = 0.119.

rate of effusion of carbon monoxide : rate of effusion of chlorine =

= 0.189 : 0.119 / ÷0.119.

rate of effusion of carbon monoxide : rate of effusion of chlorine = 1.59 : 1.

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Calculate the concentration of IO−3 in a 1.65 mM Pb(NO3)2 solution saturated with Pb(IO3)2 . The Ksp of Pb(IO3)2 is 2.5×10−13 .

lara31 [8.8K]

Answer:

See explaination

Explanation:

1) Pb(NO3)2 => Pb2+ + 2 NO3-

[Pb2+] = [Pb(NO3)2] = 7.56 mM = 7.56 x 10-3 M

Pb(IO3)2 <=> Pb2+ + 2 IO3-

Ksp = [Pb2+][IO3-]2 = 2.5 x 10-13

7.56 x 10-3 x [IO3-]2 = 2.5 x 10-13

[IO3-] = 5.75 x 10-6 M ≈ 5.8 x 10-6 M

(2) [Pb2+] = 1.7 x 10-6 M

Ksp = [Pb2+][IO3-]2 = 2.5 x 10-13

1.7 x 10-6 x [IO3-]2 = 2.5 x 10-13

[IO3-] = 3.83 x 10-4 M

[IO3-]from Pb(IO3)2 = 2 x [Pb2+]

= 2 x 1.7 x 10-6 = 3.4 x 10-6 M

[IO3-]from NaIO3 = [IO3-] - [IO3-]from Pb(IO3)2

= 3.83 x 10-4 - 3.4 x 10-6

= 3.80 x 10-4 M

NaIO3 => Na+ + IO3-

[NaIO3] = [IO3-]from NaIO3

= 3.80 x 10-4 M ≈ 3.8 x 10-4 M

7 0

4 years ago

When 4.41g of phosphoric acid (H3PO4) react with 9.25g of barium hydroxide, water and insoluble barium phosphate form. [T/I-7] a

AnnZ [28]

Answer:

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

Explanation:

Let's consider the unbalanced equation that occurs when phosphoric acid reacts with barium hydroxide to form water and barium phosphate. This is a neutralization reaction.

H₃PO₄(aq) + Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

We will balance it using the trial and error method.

First, we will balance Ba atoms by multiplying Ba(OH)₂ by 3 and P atoms by multiplying H₃PO₄ by 2.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

Finally, we will get the balanced equation by multiplying H₂O by 6.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

3 0

3 years ago

Help pleaseeeeeeeeeeeeeeeeeee

Nataly [62]

Answer:

1) Constructive Interference

2) Hits a surface and bounces back

3) Antinodes

7 0

3 years ago

Read 2 more answers

What is the solubility of KI at 10C?

Bingel [31]

31.2g per 100g of water.

Explanation:

The required result about the solubility of KI at 10C is measured to be 31.2g per 100g of water.
Every solution contains a volume and that gets changed radically when the dissolution comes into existence. The result can be seen by inspecting the solubility in mol⋅L−1.
If we look closely to understand the solubility of KI, either at 10C or at any other temperature, you can ease it by a trick. The solubility of potassium bromide is approx twice its value.

6 0

3 years ago

4.How many atoms of silver are in 100 grams of silver?

zvonat [6]

Answer:

5.58x1023Agatoms 5.58 x 10 23 A g a t o m s

Explanation:

After determining the moles of the sample, we can convert it to the number of atoms using the Avogadro's number.

4 0

3 years ago