Answer:
6.02×10²³ particles / 1 mol
Explanation:
In this question the choices are missed.
For determine the particles of Na, in 0.25 moles we should know that the mole referrs to the Avogadro's number.
1 mol of anything contains 6.02×10²³ entities, that's why we should apply this conversion factor to find the final answer:
0.25 mol . 6.02×10²³ particles / 1 mol = 1.50×10²³ particles
In conclussion: 1.50×10²³ particles of Na are contained in 0.25 moles of Na
The mole ratio can be seen below and the volume of each precipitate is 60 mL.
A mole ratio refers to a conversion factor that compares the quantities of two chemicals in moles in a chemical laboratory experiment.
<u>Mole ratio For 1:</u>
- = 10 mL : 50 mL
- = 1 : 5 mL
<u>Mole ratio For 2:</u>
<u>Mole ratio For 3:</u>
<u>Mole ratio For 4:</u>
<u>Mole ratio For 5:</u>
<u>Mole ratio For 6:</u>
<u>Mole ratio For 7:</u>
Since the parameters from the left side of the diagram are not shown, we will assume that the volumes for each precipitate are the addition of both volumes in each column.
By doing so, we have:
1.
2.
3.
4.
5.
6.
7.
Learn more about mole ratio here:
brainly.com/question/19099163
A scientist adds heat to each of the following substances.The one that<span> will probably absorb the most heat before its temperature changes significantly is
</span> 50 g of liquid water
because water has larger heat capacity
so correct option is C
hope it help
Answer:
b) the gases will mix closer to the end that holds the heavier gas.
Explanation:
The question is based on the Graham's law of diffusion.
- According to Graham's law of effusion, the rate of effusion of gases is dependent on the density of the gases. Such that the rate of effusion a gas is inversely proportional to the square root of its density.
- Therefore, a lighter gas effuses faster compared to a heavier gas.
- In this case, the gases will mix closer to the end that holds the heavier gas, because the lighter gas will effuse faster and cover a longer distance compared to the heavier gas.
- For instance , if we take two gases ammonia (NH4) and Chlorine (Cl2), if they were allowed to effuse from opposite ends of a long tube, then NH4 would effuse faster since it is lighter than chlorine. Consequently, the two would mix near the end that holds chlorine gas.
<h3><u>Answer;</u></h3>
Ka == 1.153 × 10^-4
<h3><u>Explanation</u>;</h3>
Weak acid is HA;
Equilibrium: HA(aq) + H2O(l) <=> H3O^+(aq) + A^-(aq)
Ka = [H3O^+][A^-]/[HA]
[H3O^+] = [A^-] = (0.0125)(0.738)
= 0.00923 M and [HA]
= 0.738 M - 0.00923 M = 0.738 M because the value 0.00923 is insignificant in this case.
Ka = (0.00923)^2/(0.738)
<u>= 1.153 × 10^-4</u>
