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2 years ago

bronwyns mows 12,000ft in 2/3 hours and her brother can mow 15,000ft in 3/4 hours. who mows in less times

Mathematics

1 answer:

Svet_ta [14]2 years ago

7 0

Answer:

The brother does

Step-by-step explanation:

browyns take 40 minutes, 12,000/40= 300ft a minute

brother takes 45, 15,000/45= 333ft a minute

333>300

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What number is 18% more than 1257 Round your answer to two decimal places needed,

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3 years ago

A sample of 100 people is classified by gender (male/female) and by whether they are registered voters. The sample consists of 8

uysha [10]

Answer:

Step-by-step explanation:

Given :

Male Female Total

Registered 60

Non registered 40

Total 20 80

Solution :

N= 100

Formula of expected frequency = $E_{ij}=\frac{T_i \times T_j}{N}$

$E_{ij}$ = expected frequency for the ith row/jth columm.

$T_i$ = total in the ith row

$T_j$ = total in the jth column

N = table grand total.

So, using formula $E_{11}=\frac{T_1 \times T_1}{100}$

$E_{11}=\frac{60 \times 20}{100}$

$E_{11}=12$

$E_{12}=\frac{T_1 \times T_2}{100}$

$E_{12}=\frac{60 \times 80}{100}$

$E_{12}=48$

$E_{21}=\frac{T_2 \times T_1}{100}$

$E_{21}=\frac{40 \times 20}{100}$

$E_{21}=8$

$E_{22}=\frac{T_2 \times T_2}{100}$

$E_{22]=\frac{80 \times 40}{100}$

$E_{22}=32$

Expected frequency table

Male Female Total

Registered 12 48 60

Non registered 8 32 40

Total 20 80

So, the expected frequency for males who are registered voters are $E_{11}=12$

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3 years ago

Write the equation of the line passing<br> through the point (2, -1) with a slope of -3.

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Answer:

y = -3x + 5

Step-by-step explanation:

(2, -1); m = -3

y - y1 = m(x - x1)

y + 1 = -3(x - 2)

y + 1 = -3x + 6

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3 years ago

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Step-by-step explanation: We are given a rectangle inside a regular hexagon in the figure.

We know that each side of a regular hexagon has same measure, so the measure of each side is

a = 18 units.

Therefore, the area of the regular hexagon is given by

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Since the rectangle has length and breadth of 21 units and 18 units respectively, so the area of the rectangle is

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Thus, the area of the shaded region in the figure will be

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