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3 years ago

What is the area of the shaded region?

Mathematics

1 answer:

kolezko [41]3 years ago

6 0

Answer:

110 cm^2

Step-by-step explanation:

The first thing that you need to do is find the area of triangle AFE. The area of a triangle is always base*height/2. So in this case, that would be 10*6 divided by 2, which is 30 cm. Next, you will need to know the area of triangle ECB. Using that same formula, you will get 8*10/2, which is 40 cm. Finally, you will need to find the area of the whole rectangle. The area of a rectangle is always the length times the width. In this case, you would have 10*18, which is 180 cm. To get your final answer, you need to subtract the areas of the unshaded area from the whole area. That would be 180-(30+40), which is 110 cm. I hope this helped!

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G(r)=-(r+11)(r+14) <br><br>what are the zeros & what is the vertex

Nitella [24]

Answer:

The roots (r) or the Zeros ( other name ) = -11 and -14

Step-by-step explanation:

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7 0

3 years ago

A consumer survey conducted in two consecutive years determined that a fixed baskets of goods and services cost $95.00 in year 1

Gnesinka [82]

Answer:

1.315%

Step-by-step explanation:

Given:

Prices:

Year 1 =old price =$95

Year 2 = new price = $96.25

The inflation rate is the difference in price between two Given period :

Inflation rate :

(Change in price / old price) * 100%

((New price - old price) / old price) * 100%

((96.25 - 95) / 96) * 100%

= (1.25 / 95) * 100%

= 0.0131578 * 100%

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3 0

3 years ago

Help me out please!!!!!

MAVERICK [17]

Answer:

the answer is D

Step-by-step explanation:

that is R ND Q re on the same line as well as S ND

6 0

3 years ago

Step 3: Now multiply the values to get 14,918,904,000. That is almost 15 billion passwords.

Troyanec [42]

The number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600

<h3>How to determine the number of passwords</h3>

The given parameters are:

Password length = 8

Letters = 6

Numbers = 2

There are 26 letters and 10 digits.

Since the letters and the numbers can be repeated, then the number of passwords is:

Count = 26^6 * 10^2

Evaluate

Count = 30891577600

Hence, the number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600