SOMEONE PLEASE HELP ITS DUE IN 2 HOURS

Mathematics

1 answer:

max2010maxim [7]2 years ago

6 0

Answer:

Do you need help still? I know how to do it????

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Given a line and a point not on the line

erik [133]

Answer:

Step-by-step explanation:

collinear means they are one the same line not possible, the point defines the plane exists and the line shows the structure if the plane

8 0

3 years ago

The population of new york city in 2013 was about 8,406,000 people which number best appoximates the population as a single digi

dsp73

Answer:

8 * 10^6

Step-by-step explanation:

The question is asking us to represent the value 8,406,000 in standard. The standard form of an expression is expressed as;

A * 10^n

A is any integer between 1 and 10

n is any integer.

Given the value 8,406,000

8,406,000.

We are going to move the decimal point at the end to first digit value. This point will be shifted 6 times to have;

8,406,000 = 8.6 * 10^6 (Note that n is positive since the value given is greater than 1)

Since we are to express as a single digit times a power of ten, the required answer will be 8 * 10^6

4 0

3 years ago

From a deck of five cards numbered 2, 4, 6, 8, and 10, respectively, a card is drawn at random and replaced. this is done three

Serga [27]

Since the sum of the numbers on the three draws is 12, if we want the card numbered 2 to be drawn exactly two times, the third card can only be numbered 8. In fact, $2+2+8 = 12$ , and there are no other possibilities, unless you consider the various permutations of the terms.

So, we have three favourable cases: we can draw 2,2,8, or 2,8,2, or 8,2,2. This are the only three cases where the card numbered 2 is drawn exactly two times, and the sum of the number on the three draws is 12.

Now, the question is: we have three favourable cases over how many? Well, we have 5 possible outcomes with each draws, and the three draws are identical, because we replace the card we draw every time.

So, we have 5 possible outcomes for the first draw, 5 for the second and 5 for the third. This leads to a total of $5 \times 5 \times 5 = 5^3 = 125$ possible triplets.