Question

2.1a - Fnet / m = a (11/8)

Answer 1

Explanation:

According to the free body diagram attached below, there are only two forces that are acting upon the block, namely the force tension of the rope acting upwards and the weight of the block acting downwards.

Therefore, the magnitude of the net (resultant) force exerted on the block is

                                            $\vec{F}_{\text{net}} \ = \ \vec{F}_{\text{tension}} \ - \ \vec{F}_{\text{weight}} \\ \\ \vec{F}_{\text{net}} \ = \ 250 \ \text{N} \ - \ 120 \ \text{N} \\ \\ \vec{F}_{\text{net}} \ = \ 130 \ \text{N}$.

Since the magnitude of $\vec{F}_{\text{tension}}$ > magnitude of $\vec{F}_{\text{weight}}$, this implies that the block will accelerate upwards.