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Physics

2 answers:

FrozenT [24]3 years ago

8 0

Answer:

Hey guess what there's no question genius

Explanation:

Nadusha1986 [10]3 years ago

3 0

Where the question I don’t see it but thanks for the points

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Which of the following is not a component of a normal experiment?

MaRussiya [10]

Answer:

D. Validity group

Explanation:

A validity group is not necessarily a component of a normal experiment.

A normal experiment is made up of the dependent variables, independent variables, and most times the control group.

The dependent variable is one that relies on the outcome of the effect produced from the experimental design
The independent variable is the one that causes a desired effect under the study.
The control group is a group that does not receive any treatment nor attenuation of the conditions.

4 0

2 years ago

You are an industrial engineer with a shipping company. As part of the package- handling system, a small box with mass 1.60 kg i

wlad13 [49]

Answer:

a) V = 0.82m/s

b) Vmax = 0.985 m/s

Explanation:

By conservation of energy we know that:

Eo = Ef $\frac{m*V^{2}}{2}-\frac{K*Xmax^{2}}{2}=-Ff*Xmax$

Solving for V we get:

V = 0.82 m/s

To find the maximum speed we will do the same to an intermediate point where the compression is X and the distance for the work donde by frictions is given by (Xmax - X) = (0.28m - X):

$\frac{m*Vmax^{2}}{2}+\frac{K*X^{2}}{2}-\frac{K*Xmax^{2}}{2}=-Ff*(Xmax-X)$

Then we have to solve for V, derive and equal zero in order to find position X. After solving the derivative we get:

X = 0.1m Replacing this value into the equation for Vmax:

Vmax = 0.985m/s

6 0

3 years ago

If the velocity of a body changes from 13 m/s to 30 m/s while undergoing constant acceleration, what's the average velocity of t

Ronch [10]

Since the acceleration is constant, the average velocity is simply the average of the initial and final velocities of the body:

$v_{avg} = \frac{v_f+v_i}{2}=\frac{30 m/s+13 m/s}{2}=21.5 m/s$

We can proof that the distance covered by the body moving at constant average velocity $v_{avg}$ is equal to the distance covered by the body moving at constant acceleration a: