Answer:
h = 13.06 m
Explanation:
Given:
- Specific gravity of gasoline S.G = 0.739
- Density of water p_w = 997 kg/m^3
- The atmosphere pressure P_o = 101.325 KPa
- The change in height of the liquid is h m
Find:
How high would the level be in a gasoline barometer at normal atmospheric pressure?
Solution:
- When we consider a barometer setup. We dip the open mouth of an inverted test tube into a pool of fluid. Due to the pressure acting on the free surface of the pool, the fluid starts to rise into the test-tube to a height h.
- The relation with the pressure acting on the free surface and the height to which the fluid travels depends on the density of the fluid and gravitational acceleration as follows:
P = S.G*p_w*g*h
Where, h = P / S.G*p_w*g
- Input the values given:
h = 101.325 KPa / 0.739*9.81*997
h = 13.06 m
- Hence, the gasoline will rise up to the height of 13.06 m under normal atmospheric conditions at sea level.
I think it’s B I could be wrong but I tried lol
Advantages of copper cables are that copper is an extremely powerful conductor of electricity and much more stable over time. It can withstand higher temperatures than aluminum and is more resistant to damage.
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Advantages of steel cables are that steel does not rust, is fairly cheap and readily available. It has a higher tensile strength too.
Disadvantages: Steel cables are less ductile and are therefore more susceptible to fatigue.
Answer:
Material medium
compressions and rarefactions
Explanation:
A sound wave is an example of a mechanical wave. All mechanical waves require a material medium for propagation. The medium for the propagation of sound is air. This is the reason why, if you cover your mouth, it will be difficult for another person to hear whatever you are saying.
Sound is also a longitudinal wave. Longitudinal waves are described in terms of compressions and rarefactions. Compressions refer to areas where air molecules crowd together while rarefactions refer to areas where the air molecules spread out.
Answer
The frequency and the period are 45 cycles/second and 0.023 seconds
Explanation:
The frequency of the engine is given by :

We have, the engine increases its performance from zero to 2700 rpms.
Frequency,

The time period of the engine is given by :
T = f/f
So,

Hence, the required frequency and the period are 45 cycles/second and 0.023 seconds respectively.