HELP ITS FOR 25 POINTS, i really needa finish

Mathematics

1 answer:

SSSSS [86.1K]2 years ago

8 0

Answer:

Which gas creates the longest wavelength?

→Argon gas

Which gas creates the shortest wavelength?

→ Fluorine gas

Explaination:

1.0×10^-6 > 1.0×10^-7 > 1.0×10^-10 (a^-n =1/a^n)

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How do you find the median of a data set when you have an even number of values?

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Answer:

If there is an even number of numbers, the median is the average of the two numbers in the middle.

Step-by-step explanation:

To find the median of any set of numbers, put them in order from smallest to greatest. If a number occurs more than once, list it more than once. The number in the middle is the median. If there is an even number of numbers, the median is the average of the two numbers in the middle. For your first example, we line them up: 3, 6, 6.

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Solve the following Sin 42 = cos ____

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Identify what property ( Commutative identity distributive, or associative) is used.

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10. Given matrices A, B, and C below, perform the indicated operations if possible. If the operation is not possible, explain wh

Artemon [7]

Answer(a):

Order of matrix A = 3x3 {because number of rows=3, number of columns=3}

Order of matrix B = 3x3

Order of matrix C = 1x3

3A will be of order 3x3 because multiply by scalar doesn't change the order. Which is same as the order of matrix B.

So 3A+B is possible.

We simply multiply all elements of A with 3 and add them with corresponding elements of B.

$3\begin{bmatrix}2 & -1& 0\\ 0 & 5& 0.3\\ 1 & 4&10 \end{bmatrix}+\begin{bmatrix}5 & 0& 2\\ 1 & -3& 9\\ 2 & 0& 4\end{bmatrix}= \begin{bmatrix}11 & -3& 2\\ 1 & 12& 9.9\\ 5 & 12& 34\end{bmatrix}$

Answer(b):

2B will be of order 3x3 because multiply by scalar doesn't change the order. Which is NOT same as the order of matrix C.

So 2B+C is NOT possible.

Answer(c):

CA is possible only if

number of columns of C = number of columns of A

3=3

which is true hence CA is possible.

$\begin{bmatrix}1 &3 &5 \end{bmatrix}*\begin{bmatrix}2 & -1& 0\\ 0 & 5& 0.3\\ 1 & 4&10 \end{bmatrix}=\begin{bmatrix}1*2+3*0+5*1 & 1*-1+3*5+5*4 & 1*0+3*0.3+5*10\end{bmatrix}$