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2 years ago

Which point is located at on the vertical number line?

Mathematics

1 answer:

Digiron [165]2 years ago

6 0

Answer:

b is the vertical line while y is the horizontal

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Type the integer that makes the following addition sentence true:<br> = 6<br> 39 +

quester [9]

-33

Hope this helps. :)))))

8 0

3 years ago

Which set of numbers may represent the sides of a triangle

Trava [24]

Answer:

C.(6, 4,2)

since every element of B is also an even number,so is an element of C

8 0

3 years ago

Shaun's savings can be modeled by the regression equation y = 6x^2 + 75x+200. Which of the following is the best prediction for

kipiarov [429]

Answer:

Option D

Step-by-step explanation:

The equation to predict the amount saved is

$y = 6x ^ 2 + 75x + 200.$

Assuming that the variable x represents the saving months, then substitute $x = 25$ in the quadratic equation and solve for y.

$y = 6 (25) ^ 2 +75 (25) +200\\\\y = \$\ 5,825$

The answer is the option D $5,825

3 0

3 years ago

How many solutions does the system have? \begin{cases} 3x+y=8 \\\\ 2x+2y=8 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ 3x+y=8 2x+2y=8 Choose 1

ELEN [110]

Answer:

This system has one solution (x=2 and y=2), then the answer is A.

Step-by-step explanation:

The system of equations is:

$3x+y=8$ (1)

$2x+2y=8$ (2)

Let's multiply the first equation by 2 and subtract it to the second equation

$6x-2x+2y-2y=16-8$

$4x=8$

$x=2$

Using this value in (1) we can find y.

$3(2)+y=8$

$6+y=8$

$y=2$

Therefore, this system has one solution (x=2 and y=2), the answer is A.

I hope it helps you!

3 0

3 years ago

A tutor gives John 5 assignments and asks him to complete 5. How many possible combinations? Pls answer ASAP

Fittoniya [83]

Answer:

There is 1 possible combination

Step-by-step explanation:

There are 5 assignments and they must be completed. 5. We want to find the number of combinations, then we use the formula of combinations.

$nCr =\frac{n!}{r!(n-r)!}$

Where n is the total number of objects and you choose r from them

Then

$n= 5\\\\r = 5$

$5C5 =\frac{5!}{5!(5-5)!}$

$5C5 =\frac{5!}{5!(0)!}$

$5C5 =\frac{5!}{5!}$

$5C5 =1$

7 0

3 years ago