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Yuliya22 [10]
2 years ago
5

Is it A,B,C or D I´m stuck on this..

Mathematics
2 answers:
gregori [183]2 years ago
6 0

Answer:

c. 51

Step-by-step explanation:

gulaghasi [49]2 years ago
3 0

Answer d

Step-by-step explanation:d

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Use rounding to estimate the product.<br><br> 11.45 × 5
a_sh-v [17]

Answer:

57.3

Step-by-step explanation:

just rounded up one

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3 years ago
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Find the coordinates of the transformed image when the pre-image is reflected over the line x=2
zepelin [54]
A’= (10,1)
B’= (8,1)
C’= (9,5)
D’= (7,5)

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The total amount of money, m, earned by washing cars at a school fundraiser is proportional to the number of cars, c, washed at
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M=c•p

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3 years ago
In the following triangle theta=60.Find the values of the angles of the angles B and B'
Contact [7]

Answer:

180-60 = 120 if triangle is not equilateral it cannot be isosceles then depending where the angles are they will show  60,60,60 if equilateral

For isosceles it would need to be 58 61 61 as 60, 60,60 cannot be isosceles.

Vectors 60 if right angled triangle = 90-60 = 30

So angles = 30 and 90 degree or just 120 if angle theta is a vector as explained below.

Step-by-step explanation:

Statement: If two vectors are represented by the sides of a triangle both in magnitude and direction taken in order, the resultant sum of the vectors is given by the closing third side of the triangle taken in the reverse order both in the magnitude and direction

5 0
3 years ago
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
3 years ago
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