Answer:
Yea.....where is the article and the 6 questions?
<span> first of all by using Gay Lussac Volume
1L of N2 reacts with 3L of H2
so that it can give 2L of NH3
so1.2L of N2 reacts with 3.6L of H2
so that it can give 2.4L of NH3 at same temp and pressure
hope it helps
</span>
Answer:
4.2 mL
Explanation:
- CuO(s) + H₂SO₄(aq) --> CuSO₄(aq) + H₂O(l)
We require 0.025 mol CuSO₄ and the ratio is 1:1, thus<em> we need 0.025 mol H₂SO₄.</em>
We know that the concentration of H₂SO₄ is 6.0 M, so we use the formula
- Concentration = moles / Volume
And <u>solve for volume</u>:
- Volume = moles / Concentration
- Volume = 0.025 mol / 6.0 M
- Volume = 4.2 x10⁻³ L = 4.2 mL