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Paladinen [302]
3 years ago
15

CICLOS BIOGEOQUIMICOS: lugares en que encontramos el elemento del ciclo separando en bioticos y abioticos

Chemistry
1 answer:
scoundrel [369]3 years ago
3 0

Answer:

Los ciclos biogeoquímicos son definidos como la circulación de los elementos químicos entre organismos biológicos (es decir, el factor biótico del ciclo), y componentes geológicos inorgánicos del sistema (factores abióticos). En el ciclo del agua, por ejemplo, este elemento se encuentra esparcido en los ríos y arroyos, como así también en la atmósfera, desde donde fluye como lluvia hasta el suelo y puede ser ingerida por organismos vivos terrestres y es utilizada para llevar a cabo diversas funciones celulares.

Explanation:  

Los ciclos biogeoquímicos establecen un vinculo entre los factores bióticos y abióticos del ecosistema, de modo que la energía puede fluir libremente a través de ambas partes del sistema. Los seres vivos necesitan diferentes elementos químicos para sobrevivir, los cuales forma parte de los ciclos biogeoquímicos. En los ciclos biogeoquímicos los elementos se conocen como 'nutrientes' (micro y macronutrientes). Estos elementos se encuentran esparcidos tanto en la corteza de la tierra como en la biósfera. Los nutrientes son indispensables porque de ellos depende de que la energía fluya entre el componente inorgánico y orgánico del ciclo. Por otra parte, los nutrientes también circulan dentro del ciclo entre componentes bióticos de la cadena trófica, con lo cual no sólo los nutrientes sino también la energía fluye entre organismos, desde aquellos más basales en el sistema tales como plantas (ecosistemas terrestres) o algas (marinos), hasta los niveles superiores representados por especies animales hervívoras y carnívoras de tales ecosistemas.

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2 years ago
For the reaction: N2O5(g) \longrightarrow⟶ 2NO2(g) + 1/2O2(g)
ivanzaharov [21]
The given equation from the problem above is already balance,
                                 N2O5 ---> 2NO2 + 0.5O2
Since, in every mole of N2O5 consumed, 2 moles of NO2 are formed, we can answer the problem by multiplying the given rate, 7.81 mol/L.s with the ratio.
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                       = 15.62 mol/L.s
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5 0
3 years ago
List some Industrial plants and indicate the gaseous pollutants they emit​
mixas84 [53]

Answer:

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3 0
3 years ago
Problem Page Question It takes to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbo
Marizza181 [45]

This is a incomplete question. The complete question is:

It takes 348 kJ/mol to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon. Round your answer to correct number of significant digits

Answer: 344 nm

Explanation:

E=\frac{Nhc}{\lambda}

E= energy  = 348kJ= 348000 J  (1kJ=1000J)

N = avogadro's number = 6.023\times 10^{23}

h = Planck's constant = 6.626\times 10^{-34}Js


c = speed of light = 3\times 10^8ms^{-1}

348000=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\lambda=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{348000}

\lambda=3.44\times 10^{-7}m=344nm    1nm=10^{-9}m

Thus the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon is 344 nm

5 0
3 years ago
Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. The energy of one photon of this
Sedbober [7]

<u>Answer:</u> The energy of one photon of the given light is 3.79\times 10^{-19}J

<u>Explanation:</u>

To calculate the energy of one photon, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

\lambda = wavelength of light = 525nm=5.25\times 10^{-7}m        (Conversion factor:  1m=10^9nm  )

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{5.25\times 10^{-7}mm}\\\\E=3.79\times 10^{-19}J

Hence, the energy of one photon of the given light is 3.79\times 10^{-19}J

3 0
3 years ago
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