Your answer should be 31
Tell me if it was correct?
Thanks!
DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
Answer:
<h2>
A = 22.5π ft² ≈ 70.686 ft²</h2>
Step-by-step explanation:
A = π×(2.5)² + π×2.5×6.5 = 6.25π + 16.25π = 22.5π ≈ 70.686 ft²
{6.5 ft is not a height, it's slant length}
(2x2x2)(2x2)
=2x2x2x2x2
=2x2x2x2x2
=32
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