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3 years ago

Where did you get the 300?

Mathematics

1 answer:

stellarik [79]3 years ago

7 0

What’s the question here ????

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12x15y=4140; x+y= ? solve.

Semenov [28]

Answer: The number of $12 tickets and $15 sold are 120 and 180 respectively.

Step-by-step explanation:

The given equation is:

12x + 15y = 4140 .....(1)

Where,

x stands for $12 tickets and y stands for $15 tickets

According to the question:

x + y = 300 ....(2)

Now solving equation 1 and 2.

From equation 2:

x = 300 - y

Now putting this expression in equation 1.

12x + 15y = 4140

12(300 - y) + 15y = 4140

3600 - 12y + 15y = 4140

3600 + 3y = 4140

3y = 4140 - 3600

3y = 540

y = 180

And,

x = 300 - y = 300 - 180 = 120

The number of $12 tickets sold = x = 120

The number of $15 tickets sold = y = 180

Thus, the number of $12 tickets and $15 sold are 120 and 180 respectively.

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3 years ago

461 divided by 3 place the digit

Gekata [30.6K]

I believe it's 153..

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3 years ago

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Ethan burns 650 calories when he runs for 1 hour. Soppose he runs 5 hours in one week

alex41 [277]

650 x 5=3250 calories

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3 years ago

Help me please. Im giving 20 points.

borishaifa [10]

Answer:

Isn't it 54? im not really sure

Step-by-step explanation:

6x9 = 54

4 0

3 years ago

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M is the midpoint of AN, A has coordinates

maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

Figure :-

$\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$} \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}$

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

$\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}$

On using this formula ,

$=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}$

8 0

3 years ago

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