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2 years ago

Which of the following is equivalent to: −−(2+5)−(3−7)?

Mathematics

1 answer:

Umnica [9.8K]2 years ago

3 0

Answer:

You haven't provided expressions, so I can work out the problem for you. When we divide fractions, remember always "keep, switch, flip!" That's what we're gonna do here. We keep the 2/5, switch the sign to multiplication, and flip the 7/8 to 8/7. Therefore, we have 2/5*8/7. That gives us 16/35. Hope this helps!

Step-by-step explanation:

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Please answer for brainliest what is a word problem for 5x + 10 ≥ 50

scoundrel [369]

Use this word problem just change the numbers

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3 years ago

What is the best prediction of the amount of money earned when the lemonade stand has been open for 9 hours

abruzzese [7]

Answer: $50

Step-by-step explanation: Draw a line through the apparent center of the scattered dots. See where that line intersects 9 in the time scale (x-axis numbers) and the dollars earned scale (y-axis numbers)

It could be 50 or 55, but since there are a few more dots below the apparent midline, it may be best to use the lower estimate.

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2 years ago

Simplify and leave in radical form. 8√x^2 y^6

IrinaK [193]

Step-by-step explanation:

$\sqrt[8]{ {x}^{2} {y}^{6} } \\ \\ = ( {x}^{2} {y}^{6} )^{ \frac{1}{8} } \\ \\ = {x}^{2 \times \frac{1}{8}} {y}^{6\times \frac{1}{8}} \\ \\ = x^{\frac{1}{4}} {y}^{3\times \frac{1}{4}} \\ \\ = x^{\frac{1}{4}} {y}^{\frac{3}{4}} \\ \\ = \sqrt[4]{x {y}^{3} } \\$

4 0

3 years ago

A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit

m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

$P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792$

Hence, the probability that the message will be wrong when decoded is 0.05792

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2 years ago

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scoundrel [369]

Answer:

0.2

Hope this helps!

xoxo,

cafeology

7 0

3 years ago