Answer:
892 Hz or 842 Hz
Explanation:
Given
The frequency of first guitar is 867 Hz
Beat is produced for every 0·04 s
∴ Beat has a time period of 0·04 s
<h3>Beat frequency is defined as the inverse of the time period of the beat </h3>
Beat frequency = 1 ÷ (Time period) = 1 ÷ 0·04 = 25 Hz
Let the frequency of the second guitar be f Hz
<h3>Beat frequency is defined as the absolute difference between the two frequencies</h3>
∴ Beat frequency = (867 - f) or (f - 867)
First case
25 = 867 - f ⇒ f = 842 Hz
Second case
25 = f - 867 ⇒ f = 892 Hz
∴ Possible frequencies of second guitar could be 892 Hz or 842 Hz
Answer:
Explanation:
ω = √k/m = √(33.9/0.28) = 11 rad/s
(a) maximum speed of the oscillating mass
vmax = ωA = 11(0.05) = 0.55 m/s
(b) speed of the oscillating mass when the spring is compressed 1.5 cm
The portion of total energy that is not spring potential is kinetic
½kA² - ½kx² = ½mv²
v = √(k(A² - x²)/m) = √(33.9(0.05² - 0.015²)/0.28 = 0.52482... ≈ 0.52 m/s
(c) speed of the oscillating mass as it passes the point 1.5 cm from the equilibrium position
Different wording, but same question as part (b) 0.52 m/s
(d) value of x at which the speed of the oscillating mass is equal to one-half the maximum value m
The portion of total energy that is not kinetic is spring potential
½kA² - ½mv² = ½kx²
x = √(kA² - m(vmax/2)²) / k) = √(33.9(0.05²) - 0.28(0.55/2)²) / 33.9)
x = 0.043305...≈ 4.3 cm
Answer: A surface wave is a wave that moves along the interface of two different materials, like air and water.
I think the answer is <span>AM radio </span><span>waves. Im not sure but if its right can you mark my brainliest?
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Answer:
The planes´s horizontal distance is DH = 13845 meters
Explanation:
We need to get the vector components because we already know the distance and the angle so using the trigonometric identity of Cos(Ф) we can get the horizontal component and if we get the component on x axle like 22000 (m)*Cos(51°) = x so we can find that x = 13845.05 meters