Answer:
There are two popular forms of softball, distinguished by the type of pitch.
Explanation:
Softball refers to a kind of sports that is similar to baseball in terms of game play but softball is played with a larger ball. The game of softball was first introduced as an indoor game in Chicago, Illinois, United States of America in the year 1887. Also, the field for playing softball is relatively smaller than that of baseball and as such its game play is quite faster.
Some of the kits and paraphernalia used for playing softball are base, bat, softball, gloves, jerseys etc.
There are two (2) main types of softball game and these are;
I. Fast-pitch softball.
II. Slow-pitch softball.
Hence, the true statement regarding softball is that, there are two popular forms of softball, distinguished by the type of pitch.
Explanation:
One of the takeaways of the General Theory of Relativity (GTR) was that the light can be curved because of the gravity of a massive object. Einstein had proposed the idea of <em>space-time</em> fabric. Every object having mass will create depression in this fabric. Heavier the object, bigger the depression. Thus when light will pass near a heavy object lets say our Sun, it will deflect. He also gave mathematical formula to calculate the deflection.
The same was proved during the Total Solar Eclipse of 29 May 1919. Two scientists named Arthur Eddington and Frank Dyson conducted an experiment. In this eclipse the Sun was to be in front of Hyades in Taurus constellation. They took the measurement of stars of Hyades visible during the eclipse and then compared them with the actual readings. The deflection was clearly visible and the amount of deflection was very close to the values predicted by General Theory of Relativity. Thus they proved the theory right.
Answer:
Explanation:
In this case we have to work with vectors. Firs of all we have to compute the angles between x axis and the r vector (which points the charges):
the electric field has two components Ex and Ey. By considering the sign of the charges we obtain that:
Hence, by replacing E1 and E2 we obtain:
![\vec{E}=[(68.67N/C)cos(90\°)-(16.52N/C)cos(17.10\°)]\hat{i}+[(68.67N/C)sin(90\°)-(16.52N/C)sin(17.10\°)]\hat{j}\\\\\vec{E}=(-15.78\hat{i}+63.81\hat{j})\frac{N}{C}](https://tex.z-dn.net/?f=%5Cvec%7BE%7D%3D%5B%2868.67N%2FC%29cos%2890%5C%C2%B0%29-%2816.52N%2FC%29cos%2817.10%5C%C2%B0%29%5D%5Chat%7Bi%7D%2B%5B%2868.67N%2FC%29sin%2890%5C%C2%B0%29-%2816.52N%2FC%29sin%2817.10%5C%C2%B0%29%5D%5Chat%7Bj%7D%5C%5C%5C%5C%5Cvec%7BE%7D%3D%28-15.78%5Chat%7Bi%7D%2B63.81%5Chat%7Bj%7D%29%5Cfrac%7BN%7D%7BC%7D)
hope this helps!!
Answer:
13 sec <===== see assumption below
Explanation:
If the cyclist is ACCELERATING at 1.2 m/s^2 ....it will not stop.
<u>If the acceleration is </u><u>-</u><u> 1.2 m/s^2 , then:</u>
vf = vo + a t
vf = final velocity = 0 vo = original v = 6.5m/s a = - 1.2 m/s^2
0 = 6.5 - 1/2 t then t = 13 sec
The answer is LESS sorry that, that other guy wouldn't help :(
