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3 years ago

1.) There are 16 juniors and 8 seniors in the Chess Club. If the club

Mathematics

1 answer:

Lena [83]3 years ago

7 0

Answer:

1.) There are 16 juniors and 8 seniors in the Chess Club. If the club members decide to send 9 juniors to a tournament, how many different possibilities are there?

(16 over 9) = 16!/(9!*7!) = 11440

2.) How many different ways can 3 cards be drawn from a deck of 52 cards without replacement?

52*51*50 = 132600

3.) How many different ways can 3 cards be drawn from a deck of 52 cards with replacement?

52^3 = 140608

4.) A corporation has 5 officers to choose from which 3 are selected to comprise the board of directors. How many combinations are there?

(5 over 3) = 5!/(3! * 2!) = 10

5.) A combination lock has the numbers 1 to 40 on each of three consecutive tumblers. What is the probability of opening the lock in ten tries?

10/40^3 = 1/6400

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Answer:

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Marina CMI [18]

Answer:

The first one and the last one

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3 years ago

Find an equation for the line with the given properties. Perpendicular to the line x - 6y = 8; containing the point (4,4) O 1) y

Pepsi [2]

Answer:

Option 3 - $y=-6x+28$

Step-by-step explanation:

Given : Perpendicular to the line $x - 6y = 8$ ; containing the point (4,4).

To Find : An equation for the line with the given properties ?

Solution :

We know that,

When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.

Slope of the equation $x - 6y = 8$

Converting into slope form $y=mx+c$ ,

Where m is the slope.

$y=\frac{x-8}{6}$

$y=\frac{x}{6}-\frac{8}{6}$

The slope of the equation is $m=\frac{1}{6}$

The slope of the perpendicular equation is $m_1=-\frac{1}{m}$

The required slope is $m_1=-\frac{1}{\frac{1}{6}}$

$m_1=-6$

The required equation is $y=-6x+c$

Substitute point (x,y)=(4,4)

$4=-6(4)+c$

$4=-24+c$

$c=28$

Substitute back in equation,

$y=-6x+28$

Therefore, The required equation for the line is $y=-6x+28$

So, Option 3 is correct.

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3 years ago

Which or the following is the radical expression of 4d3/8

stira [4]

Answer:

$\boxed{4 \sqrt[8]{ {d}^{3} } }$

Step-by-step explanation:

$= > 4 {d}^{ \frac{3}{8} } \\ \\ = > 4({d}^{3 \times \frac{1}{8} }) \\ \\ = > 4( {d}^{3} \times {d}^{ \frac{1}{8} } ) \\ \\ = > 4( {d}^{3} \times \sqrt[8]{d} ) \\ \\ = > 4 \sqrt[8]{ {d}^{3} }$

3 0

3 years ago