The answer is -1.01
I first changed the signs of the ones i could. So <span>-0.75+(2/50)+0.4(-3/4)
Then i multiplied the 0.4*-3/4 which equals -0.3
So you are left with </span><span>-0.75+(2/50)-0.3
2/50 is equal to 0.04 so now it is </span> -0.75+0.04-0.3 and the rest is simple math. Which equals -1.01
Answer:
The 8th term of the sequence is 896/2187.
Step-by-step explanation:
We want to find the 8th term of a geometric sequence whose common ratio is 2/3 and whose first term is 7.
We can write a direct formula. Recall that the direct formula of a geometric sequence is given by:
![\displaystyle x_{n} = a\left(r\right)^{n-1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x_%7Bn%7D%20%3D%20a%5Cleft%28r%5Cright%29%5E%7Bn-1%7D)
Where <em>a</em> is the initial term and <em>r</em> is the common ratio.
Substitute:
![\displaystyle x_{n} = 7\left(\frac{2}{3}\right)^{n-1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x_%7Bn%7D%20%3D%207%5Cleft%28%5Cfrac%7B2%7D%7B3%7D%5Cright%29%5E%7Bn-1%7D)
To find the 8th term, let <em>n</em> = 8. Substitute and evaluate:
![\displaystyle \begin{aligned} x_{8} &= 7\left(\frac{2}{3}\right)^{(8) - 1} \\ \\ &= 7\left(\frac{2}{3}\right)^{7} \\ \\ &= 7\left(\frac{128}{2187}\right) \\ \\ &= \frac{896}{2187} = 0.4096...\end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7D%20x_%7B8%7D%20%26%3D%207%5Cleft%28%5Cfrac%7B2%7D%7B3%7D%5Cright%29%5E%7B%288%29%20-%201%7D%20%5C%5C%20%5C%5C%20%26%3D%207%5Cleft%28%5Cfrac%7B2%7D%7B3%7D%5Cright%29%5E%7B7%7D%20%5C%5C%20%5C%5C%20%26%3D%207%5Cleft%28%5Cfrac%7B128%7D%7B2187%7D%5Cright%29%20%5C%5C%20%5C%5C%20%26%3D%20%5Cfrac%7B896%7D%7B2187%7D%20%3D%200.4096...%5Cend%7Baligned%7D)
In conclusion, the 8th term of the sequence is 896/2187.
Answer:
<h2>x = 5√3 inches</h2>
Step-by-step explanation:
Since the triangle is a right angled triangle we can use Pythagoras theorem to find the missing side x
Using Pythagoras theorem we have
![{a}^{2} = {b}^{2} + {c}^{2}](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B2%7D%20%20%3D%20%20%7Bb%7D%5E%7B2%7D%20%20%2B%20%20%7Bc%7D%5E%7B2%7D%20)
where a is the hypotenuse
Substitute the values into the above formula
The hypotenuse is 10 inches
We have
![{10}^{2} = {5}^{2} + {x}^{2}](https://tex.z-dn.net/?f=%20%7B10%7D%5E%7B2%7D%20%20%20%3D%20%20%7B5%7D%5E%7B2%7D%20%20%2B%20%20%7Bx%7D%5E%7B2%7D%20)
![{x}^{2} = {10}^{2} - {5}^{2}](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%20%20%7B10%7D%5E%7B2%7D%20%20-%20%20%7B5%7D%5E%7B2%7D%20)
![{x}^{2} = 100 - 25](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%20100%20-%2025)
![{x}^{2} = 75](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%2075)
We have the final answer as
<h3>x = 5√3 inches</h3>
Hope this helps you
Answer:
sorry I'm not in whatever grade your in
Answer:
74.86% probability that a component is at least 12 centimeters long.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 14](https://tex.z-dn.net/?f=%5Cmu%20%3D%2014)
Variance is 9.
The standard deviation is the square root of the variance.
So
![\sigma = \sqrt{9} = 3](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B9%7D%20%3D%203)
Calculate the probability that a component is at least 12 centimeters long.
This is 1 subtracted by the pvalue of Z when X = 12. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{12 - 14}{3}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B12%20-%2014%7D%7B3%7D)
![Z = -0.67](https://tex.z-dn.net/?f=Z%20%3D%20-0.67)
has a pvalue of 0.2514.
1-0.2514 = 0.7486
74.86% probability that a component is at least 12 centimeters long.