I'm assuming you only need the first triangle. You didn't specify. If you need it after I answer the first one I'll be happy to help though.
To find the area of a triangle you go b(h)/2=a
6cm(3cm)/2
18/2
Area=9
To find the perimeter you add all of the sides together.
4+4+6=P
4+10=P
14= Perimeter
Hi there!
So the format of slope-intercept form is:
y= mx+b
m= your slope
x = just a variable
b= your y- intercept
Using those hints, see if you can figure out the answer! :)
Hope this helped!
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If you're super stuck, your answer would be:
Slope: -7
Y- intercept: 12
The area of a rectangle is length*width.
The length of this 3x and the width is 2x-3. This means that, to find the area, you need to multiply 3x and 2x-3.
Start by writing out this equation:
A=l*w
Then, plug in your given values:
A= 3x*2x-3 (you can also write it as A= 3*x*2*x-3)
Then, following the order of operations, you start by multiplying. This makes your equation become A = 6x^2 -3. (^2 means squared). It turns into this because 3 * 2 is 6 and x * x is x^2 and you still haven’t used the 3 yet.
After this, there is nothing more that you can do to simplify the equation. Therefore, the area is 6x^2 - 3.
I hope this helped!
