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maw [93]
3 years ago
6

Find the volume of the sphere to the nearest whole number. Use pi = 3.14. A. 131 in. 3 B. 393 in. 3 C. 4,187 in. 3 D. 523 in. 3

Mathematics
1 answer:
Westkost [7]3 years ago
5 0
The answer is B. That's what I got
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three times the lesser of two consecutive even integers is 6 less than six times the greatest number. find the integers.
kakasveta [241]

3x-6=6(x+2)   3x-6=6x+12  3x-6x=6+12   -3x=18  X= 18/-3  X= -6  first number . For second number you substitute x+2. -6+2=-4    

3 0
3 years ago
if the measure of <BEC is (2x+3)° and x=30, which expression could represent the measure of <AED?​
Maurinko [17]

Answer:

The answer is 3x-27

Step-by-step explanation:

If the angles are vertical from each other it means they are congruent. 2x+30 is 63, you plug in the x, 2(30)+30. You do that to the second one and also get 63, 3(30)-27. Therefore 3x-21 is the answer.

8 0
2 years ago
Ooth<br> 3 12100<br> Х<br> -3<br> -2.<br> у<br> 5<br> 2<br> -1<br> 4<br> -7<br> What is the slope?
MrMuchimi
-4 that will be your answer
6 0
3 years ago
Suppose that a cyclist began a 364 mi ride across a state at the western edge of the​ state, at the same time that a car traveli
maw [93]
The car's average rate  is 43.7 mph. The bicycle's average rate is 12.3 mph.

To get this solution, let the bicycle's average rate be (x) and the car's average rate be (x + 31.4) mph. 

Distance= Speed x Time
364 = (x + x + 31.4) 6.5
364 = (2x + 31.4) 6.5
364/6.5 = 2x + 31.4
56 = 2x + 31.4
56 - 31.4 = 2x
24.6 = 2x
24.6/2 = x
12.3 = x

x = 12.3 mph     
x+31.4 = 43.7 mph
6 0
3 years ago
A simple random sample from a population with a normal distribution of 99 body temperatures has xbar = 99.10°F and s = 0.64°F. C
motikmotik

The general formula for the margin of error is e = (zs)/√n, when the sample size is 30 or more (otherwise, we'd need to to a t-interval).

Since we're needing a 99% confidence interval, we need to know what the positive z-score associated with this two-tailed area under the normal curve is.  This can be a little tricky if you're using a standard normal table.  What you want is a two-tailed interval that has an area of .99.  What this means is that the remaining 0.01 is divided into 0.005 on each end.  This then means that, to the right of the mean (which is 0), the area is 0.005 less than the total right-half area of 0.5, or 0.495.  The total cumulative area, then, includes this plus the left half of .5, or 0.5 + 0.495 = .0995.

Then, if all we have to go on is a cumulative standard normal table, then we need to find the area closest to 0.995 and find the corresponding z-score.  This z-score is 2.58.

Now that we have the z-score, we can now plug in all the values into the formula.  

e = (2.58 · 0.66)/√102 = 0.1686.

So the 99% confidence interval will be that far above and below the mean (which is 98.8).  So the lower limit is 98.8 - 0.1686 = 98.631, and the upper limit is 98.8 + 0.1686 = 98.967.

The TI-84 method:

This is much easier, if you're allowed to use this technology.  You begin with the STAT button, and then move over to the TESTS menu.  Then select ZInterval.  We have summary stats rather than data in this problem, so we select Stats as the input.  For the standard deviation, we put 0.66, for x-bar 98.8, for n 102, and for C-level 0.99.  Then select Calculate, and it will provide the interval at the top of the screen (98.632, 98.968).  Note that the lower limit is slightly different by this method.  This is because, when doing it by hand, we had to approximate the z-score.  This created a rounding error, albeit  a small one.

4 0
2 years ago
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