Find the volume of the sphere to the nearest whole number. Use pi = 3.14. A. 131 in. 3 B. 393 in. 3 C. 4,187 in. 3 D. 523 in. 3

Gretta is 1 1/2 meters tall. Which of the following is equivalent to 1 1/2 meters? A 150 millimeters B 1.500 millimeters C 100 m

Crazy boy [7]

Answer:

1500 millimeters is your answer

5 0

3 years ago

A lake has a population of a rare endangered fish. The lake currently has a population of 14 fish. The number of fish is increas

alex41 [277]

14^ 0.08t = 56.

From here, you can rewrite it as log base 14 argument 56 = 0.08t.

When you plug it in t is about 19

Answer: ≈19 years

4 0

3 years ago

A boat rental shop rents paddle boats for a fee plus an additional cost per hour. The cost of renting different numbers of hours

mylen [45]

The independent variable is that whose values do not take into account the values of other variables. That is the time in hours for this item. Then, for the dependent variable, the answer would be the cost of renting. The value of the dependent variable is based on the changes done in the values of the independent variable.

4 0

3 years ago

To date, Ty has cumulative earnings of $107,600. This week he is paid $3,000. What's the total amount of social security tax for

rjkz [21]

Ty's social security tax is
6.2% * $3000 = $186.00

The best choice is ...
A. $186.00

6 0

3 years ago

Read 2 more answers

Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th

DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that $A \cap B$ = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

$A + (A \cap B) = 0.40$

$A + 0.17 = 0.40$

$A = 0.23$

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

$B + (A \cap B) = 0.35$

$B + 0.17 = 0.35$

$B = 0.18$

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0

3 years ago