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pochemuha
2 years ago
12

Helpppppppppppppppoo

Mathematics
1 answer:
ANTONII [103]2 years ago
5 0
I can’t see the photo could you please make it bigger so I can help I
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Karen is starting a career as a professional wildlife photographer and plans to photograph Canadian Geese at one of the staging
balandron [24]

Answer:

$5000*0.816 = $4082

Step-by-step explanation:

It's a strange question, but based on the statement and the question it sounds like it's a poisson distribution:

* For 3 days she was able to get 2 good shots (<em>typical of that time of the year</em>)

* Good shots happen randomly

* Each day is independent of another

Let's call 'p' the probability that she makes a good shot per day

Let's call 'n' the number of days Karen is taking shots.

So, if in 3 days he got 2 good shots and that is typical at that time of the year, then the expected value for the number of good shots (X) is:

E(x)=\frac{2}{3}

For a Poisson distribution E (x)=\lambda\\\lambda= np

So:

\lambda =\frac{2}{3}

For a Poisson distribution the standard deviation is:

\sigma = \sqrt{\lambda}\\\sigma = \sqrt{\frac{2}{3}}

\sigma = 0.816 this is the standard deviation for the number of buentas taken.

So the standard deviation for income is the price of each shot per sigma

$5000*0.816 = $4082, which is the desired response.

3 0
3 years ago
The first time that Arnold ran for mayor in a small town, he received 5% of the votes. This year, when Arnold ran for mayor agai
sammy [17]

Answer:

20 votes

Step-by-step explanation:

You start with the percents: You always start with 100%

100-5=95

Then you multiply

95 x 4

4 is how many votes he received the 2nd time

95 x 4= 380

Then you subtract

380-360= 20

Your Welcome :)

6 0
2 years ago
In 15–20, write the number positioned at each point.
Mumz [18]

Answer:

See below.

Step-by-step explanation:

15.) -3.25

16.) -4.5

17.) 1.25

18.) -5.75

19.) 0.5

20.) -2.5

5 0
3 years ago
What are x and 8 in this lineat equation? 8/x+5=50/25
MatroZZZ [7]

Answer:

x= -8/3

Step-by-step explanation:

4 0
3 years ago
We were never taught this in class, and I understand it, kind of... but i'm just confused with everything.
GaryK [48]
\bf \cfrac{x^3y}{xy^5}\cdot \cfrac{x^2y^9}{x^8}\implies \cfrac{x^3x^2y^1y^9}{x^1x^8y^5}&#10;\\ \quad \\&#10;\textit{now, using exponent rules, same base, different exponent}&#10;\\ \quad \\&#10;\cfrac{x^{3+2}y^{1+9}}{x^{1+8}y^5}\implies \cfrac{x^5y^{10}}{x^9y^5}\\&#10;----------------------------\\\bf \textit{now, keep in mind that}&#10;\\ \quad \\&#10;a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad&#10;&#10;\cfrac{1}{a^{ n}}\implies a^{-{ n}}&#10;\\ \quad \\&#10;%  negative exponential denominator&#10;a^{{ n}} \implies \cfrac{1}{a^{- n}}&#10;\qquad \qquad &#10;&#10;\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}}&#10;\\ \quad \\&#10;thus\\&#10;----------------------------\\&#10;\bf \cfrac{x^5y^{10}}{x^9y^5}\implies \cfrac{x^5y^{10}}{1}\cdot \cfrac{1}{x^9}\cdot \cfrac{1}{y^5}\implies x^5y^{10}\cdot x^{\boxed{-9}}\cdot y^{\boxed{-5}}&#10;\\ \quad \\&#10;x^5x^{-9}y^{10}y^{-5}\implies x^{5-9}y^{10-5}\implies x^{-4}y^5&#10;\\ \quad \\&#10;\cfrac{1}{x^{\boxed{4}}}\cdot \cfrac{y^5}{1}\implies \cfrac{y^5}{x^4}
8 0
3 years ago
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