The answer -35.5 Hope this helps you
If
then
The ODE in terms of these series is
We can solve the recurrence exactly by substitution:
So the ODE has solution
which you may recognize as the power series of the exponential function. Then
Answer:
1.9 degrees above the normal temperture
Step-by-step explanation:
Normal temperture: 98.6 degrees Fahrenheit
100.5 - 98.6 = 1.9
Let p(x) be a polynomial, and suppose that a is any real
number. Prove that
lim x→a p(x) = p(a) .
Solution. Notice that
2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .
So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial
long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x –
2.
Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number
such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| <
1, so −2 < x < 0. In particular |x| < 2. So
|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|
= 2|x|^3 + 5|x|^2 + |x| + 2
< 2(2)^3 + 5(2)^2 + (2) + 2
= 40
Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2
+ x − 2| < ε/40 · 40 = ε.
Answer: x = 2 and y = -4
x + 2y = -6
x = -6-2y
Putting this in value of x in
6x + 2y = 4
6(-6-2y) + 2y = 4
-36-12y+2y = 4
-10y = 4+36
y = 40/(-10)
y = -4
Now putting this value of y in
x + 2y = -6
x + 2(-4) = -6
x -8 = -6
x = -6+8
x = 2
Therefore x = 2 and y = -4
If we put these values we can check this
x + 2y = -6
2 + 2(-4) = -6
2 -8 = -6
-6 = -6
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