Answer:
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Step-by-step explanation:
Answer: $1,261.68
Multiply the cost for one tile ($7.51) by the number of tiles being used (168)
You multiply what’s on top of that
By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is
<h3>What is
sequence ?</h3>
Sequence is collection of numbers with some pattern .
Given sequence

We can see that

and

Hence we can say that given sequence is Geometric progression whose first term is 5 and common ratio is -2
Now
term of this Geometric progression can be written as

So summation of 15 terms can be written as

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is
To learn more about Geometric progression visit : brainly.com/question/14320920
Answer:
36, 32, 28, 24
Step-by-step explanation:
Fill in the values of n and do the arithmetic.
a1 = 36 -4(1 -1) = 36
a2 = 36 -4(2 -1) = 32
a3 = 36 -4(3 -1) = 28
a4 = 36 -4(4 -1) = 24
_____
You could recognize the formula as the specific case of the explicit formula for an arithmetic sequence with first term 36 and common difference -4. That tells you the second term is 36 -4 = 32, and each successive term is 4 less than the one before.