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Vesnalui [34]
3 years ago
10

What's the answer to this?

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
8 0
3 1/4 :) mark brainliest?
LenKa [72]3 years ago
8 0

Answer:

13/4 or 3 1/4

Step-by-step explanation:

Make into improper fractions:

4x3+1 = 13, 1x3+1 = 4

13/3 ÷ 4/3

Dividing fractions rule: ALWAYS make the second one a reciprocal (flip the fraction) and then change the sign. Remember KCC, Keep, Change, Change.

So: 13/3 x 3/4

The 3's cancel leaving you with 13/4 or 3 1/4

Hope that helps. Brainliest is appreciated

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Answer:

Just flip it 180 degrees

Step-by-step explanation:

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Imagine working with a younger sibling or student who is having trouble with the 9 times table. Create an algorithm to help the
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When 9 is multiplied by a number less than eleven, add 1 to the tens place and subtract 1 from the ones place.
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3 years ago
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What are the earnings for:
Kruka [31]

Answer:

1)

$ 345

2)

$ 97.125

Step-by-step explanation:

1)

5 days at $69.00 a day.

It is given that the earning of one day is: $ 69

Hence, the earning of 5 days will be:

5\times 69\\=\$ 345

Hence, the value of a_0 is 345.

2)

3.5 days at $27.75 a day .

It is given that the earning of one day is: $ 27.75

Hence, the earning of 3.5 days will be:

3.5\times 27.75\\=\$ 97.125

Hence, the value of a_1 is 97.125.

8 0
4 years ago
Each investment matures in 3 years. The interest compounds annually.
Sveta_85 [38]

bearing in mind that 4¾ is simply 4.75.

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$600\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &3 \end{cases} \\\\\\ A=600\left(1+\frac{0.05}{1}\right)^{1\cdot 3}\implies A=600(1.05)^3\implies A=694.575 \\\\[-0.35em] ~\dotfill

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$750\\ r=rate\to 4.75\%\to \frac{4.75}{100}\dotfill &0.0475\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &3 \end{cases} \\\\\\ A=750\left(1+\frac{0.0475}{1}\right)^{1\cdot 3}\implies A=750(1.0475)^3\implies A\approx 862.032

well, the interest for each is simply A - P

695.575 - 600 = 95.575.

862.032 - 750 = 112.032.

4 0
3 years ago
Please help!!! thank you so much whoever does!!
klasskru [66]

Answer:

32 lbs

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7 0
2 years ago
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