Which ordered pair is in Quadrant III?

Mathematics

1 answer:

Scilla [17]3 years ago

4 0

(-2,-3)
I. (+,+)
II. (-,+)
III. (-,-)
IIII. (+,-)

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20 yards 8 inches is divided into 26 equal sections, how long is each section

hoa [83]

In the given question, there are several information's of immense importance and worth taking a look. based on these information's, the answer to the question can be easily determined.The length that has to be divided into 26 equal parts is 20 yards and 8 inches.Firstly we have to change the yard into inches and then we can divide the total inches into 26 equal parts.
We know
1 yard = 36 inches
20 yards = 720 inches
Then the total length that has to be divided = (720 + 8) inches
= 728 inches
Now we have to divide the 728 inches into 26 equal parts.
Length of each section = (728/26) inches
= 28 inches.
So each of the 26 parts will have a length of 28 inches.

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3 years ago

Q#7: Solve for the variable: 3(x+2) - 9 = 15 - 4(5x - 2) Make sure you round you answer to the nearest whole number.

masya89 [10]

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$\blue\textsf{\textbf{\underline{\underline{Question:-}}}}$

3(x+2)-9=15-4(5x-2)

$\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}$

First use the distributive property of both sides:-

3(x+2)-9=15-4(5x-2)

3x+6-9=15-20x+8

Now add 20x on both sides:-

23x+6-9=15+8

On simplification,

23x-3=23

Add 3 to both sides:-

23x=26

Divide by 23 on both sides:-

x=26/23

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2 years ago

A spaceship is traveling at a steady rate. The table shows the distance the spaceship travels in a given period of time. Find th

nika2105 [10]

The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.

<h3>What is the distance the spaceship travels in 4 minutes?</h3>

The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;

Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.

Consequently, we can evaluate the distance travelled after 4 minutes as;

Distance = 200 × 4 = 800mi.

Ultimately, the distance travelled per minute by the spaceship is; 800mi.

Remarks:

600 miles

520 miles

800 miles

1,080 miles