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mars1129 [50]
2 years ago
11

-4 2/3 + 2 1/2 , I need help asp for this question help someone

Mathematics
1 answer:
snow_lady [41]2 years ago
7 0

Answer:

The solution is in the attached file

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Which of the following is the best estimate of the square root of 160
Virty [35]

Answer:

12-13

Step-by-step explanation:

the actual number is 12.64 whether your round up or down is up to you

6 0
2 years ago
Read 2 more answers
Find f(x) and g(x) so the function can be expressed as y = f(g(x)). y = Two divided by x squared. + 3
kodGreya [7K]
Hello,

g(x)=x²+3
f(x)=2/x
so f(g(x))=f(x²+3)=2/(x²+3)

Explainations:

f(y)=2/y
f(4y)=2/(4y)
f(x²)=2/x²
f(x²+3)=2/(x²+3)

4 0
3 years ago
BRAINLIST!!! The area of Alex's room is 168 square feet. If his room is a rectangle and one side is 12 feet, how long is the oth
Cloud [144]

Answer:

the missing length is 14 feet.

Step-by-step explanation:

a = L × W

168ft² = 12 × W     - divide both sides of the equation by 12

                             - 168 ÷ 12 = 14

168ft² = 12 × 14

6 0
3 years ago
A ball is thrown into the air. The height in feet of the ball can be modeled by the equation, h(t) = −16t2 + 10t + 6 where t is
Lelechka [254]

A function assigns the value of each element of one set to the other specific element of another set. The correct option is D.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

The time at which the ball will hit the ground is,

h(t) = −16t² + 10t + 6

0 = -16t² + 10t + 6

8t² - 8t + 3t - 3= 0

8t(t-1)+3(t-1) = 0

(8t+3)(t-1)=0

t = -0.375, 1

Hence, the ball hit the ground at 1 second, while the function in intercept form can be written as h(t) = (−8t − 3)(2t − 2).

Thus, the correct option is D.

Learn more about Function:

brainly.com/question/5245372

#SPJ1

6 0
2 years ago
2/6, 5/12, 3/7, and 4/10. List least to most
olya-2409 [2.1K]
Turn them into percentages:
2/6=1/3=33.333%
5/12=42%
3/7=43%
4/10=2/5=40%

Now put them in order :)

2/6,4/10,5/12,3/7
7 0
2 years ago
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