Given:
In △ABC is a right angle triangle.
AC is 6 units longer than side BC.
To find:
The length of AC.
Solution:
Let the length of BC be x.
So, Length of AC = x+6
According to the Pythagoras theorem, in a right angle triangle
△ABC is a right angle triangle and AC is hypotenuse, so
![[\because (a+b)^2=a^2+2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a%2Bb%29%5E2%3Da%5E2%2B2ab%2Bb%5E2%5D)
Subtract 68 from both sides.
Divide both sides by 2.
Splitting the middle term, we get
Side cannot be negative, so x=2 only.
Now,
Therefore, the length of AC is 8 units.
Step-by-step explanation:
Equation: y = (x - 1)² + 4
Answer:
X = 9
okay If I'm wrong sry what's 9x3 it's 45 right ( me not using a caluctalter ) ( I didn't even spell that Right lol ) but anyways it's X=9
Hello once again!
When you see a question like this, you need to find the equation of the straight line.
The formular used is y = mx + c
Where
m = slope
c = constant
First find the slope, since it's a straight line, any 2 coordinates can be used.
Now we need to substitude in the slope, and one of the coordinate you used to find the slope, to the formular to find the constant.
In this case i'm using the coordinate
(-2, 16)
y = mx + c
16 = -6(-2) + c
16 = 12 + c
c = 4
∴ The equation of the line is y = -6x + 4
The next step is to simply substitude in the x = 8 to the equation to find y.
y = -6(8) + 4
y = -48 + 4
y = -44
The answer is -4 + 7. Because its subtracting 4 to zero which makes it -4. And then its adding 7 so the answer is -4+7
