*PLS HELP*I need help on this and please provide an explanation
2 answers:
Answer:
<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>9</u></em></h2>
Step-by-step explanation:
<h3>
<em><u>To</u></em> <em><u> </u></em> <em><u>Find</u></em> <em><u>:</u></em> <em><u>-</u></em> </h3>
<h3><em><u>Given</u></em><em><u>:</u></em><em><u>-</u></em></h3>
46° and (5x - 1)° are complementary angles
<h3><em><u>Solution</u></em><em><u>:</u></em><em><u>-</u></em></h3>
As we know ,
Complementary angles :
The angles whose sum results to 90° are known as the <em><u>complementary</u></em><em><u> </u></em><em><u>angles</u></em><em><u>.</u></em><em><u> </u></em>
So ,
46° + (5x - 1)° = 90°
<em>[</em><em>Since</em><em> </em><em>complementary</em><em> </em><em>angles</em><em>]</em> => 46 + 5x - 1 = 90
<em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em> => 45 + 5x = 90
<em>[</em><em>On</em><em> </em><em>subtracting</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>with</em><em> </em><em>45</em><em>]</em> => 45 + 5x - 45 = 90 - 45
<em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em> => 5x = 45
<em>[</em><em>On</em><em> </em><em>dividing</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>with</em><em> </em><em>5</em><em>]</em>
<em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em> => x = 9
<em><u>Hence</u></em> <em><u>,</u></em> <em><u> </u></em> <em><u>required</u></em> <em><u> </u></em> <em><u>value</u></em> <em><u> </u></em> <em><u>of</u></em> <em><u> </u></em> <em><u>x</u></em> <em><u> </u></em> <em><u>=</u></em> <em><u> </u></em> <em><u>9</u></em> <em><u> </u></em> <em><u>(</u></em> <em><u>Ans</u></em> <em><u>)</u></em>
<u>Answer: </u>
<u>Step-by-step explanation: </u>
<u>We know that:</u>
46 + (5x - 1) = Complementary angles = 90° <u>Solution:</u>
<em>Removal of brackets:</em>
=> 46 + 5x - 1 = 90 => 45 + 5x = 90 <em>Subtracting 45 from both sides:</em>
=> -45 + 45 + 5x = 90 - 45 <em>Solving:</em>
Hence, <u>the value of x is 9.</u>
Hoped this helped.
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