Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
I can help with the formula just do the math on a calculator you multiply length x width x height
We know that the midpoint is the a point in the center of the line (r). This means that from the midpoint to the endpoint (qr) is half the length of the overall line. This means that 5.7 (the length of qr) units is half the length of the line. Two halves make a whole so 5.7 × 2 = 11.4 units as the length of the entire line qs.
Hope this helps!