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elena-14-01-66 [18.8K]
2 years ago
9

PLEASE HELP ILL MARK YOU BRAINLIEST

Mathematics
1 answer:
mr Goodwill [35]2 years ago
7 0

Answer:

D is the correct a

Step-by-step explanation:

From table A-3: Areas under the normal curve

we can deduce that k=0.9

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X^2-5x=-4 line of symmetry
Kipish [7]
The axis of symmetry in form
y=ax^2+bx+c is -b/2a

so
y=x^2-5x+4
y=1x^2-5x+4
-b/2a=-(-5)/(2*1)=5/2
the axis of symmetry is x=5/2
6 0
3 years ago
Math can you please help me?​
jok3333 [9.3K]

Answer:

The answer will be -5

You are welcome:)

Step-by-step explanation:

4 0
2 years ago
The equation x^2-9=0 has how many real solutions
Marina CMI [18]

So remember that the <u>degree of the polynomial will indicate how many solutions there are, real or complex.</u> Since the degree of the polynomial is 2, this means that there is a maximum of 2 real solutions in this equation.

Next, we are going to apply the difference of squares rule to this polynomial, which is x^2-y^2=(x+y)(x-y) . In this case:

x^2-9=(x+3)(x-3)\\(x+3)(x-3)=0

Now, we are going to apply the Zero Product Property, which states that if a × b = 0, this means that either a or b = 0 or a and b = 0. In this case, a = x + 3 and b = x - 3. Solve each as such:

x+3=0\\x=-3\\\\x-3=0\\x=3

<u>In short, there are 2 real solutions: x = 3 and x = -3.</u>

6 0
3 years ago
The area of a parallelogram increased from 40 to 128 square centimeters what is area percentage?
Goryan [66]

Answer:

320

Step-by-step explanation:

j u s t a g u e s s b u t i t h i n k i t s r i g h t

5 0
3 years ago
If WX= 82 cm, find the length of YZ. (OV = 9cm and OV is perpendicular to YZ)
damaskus [11]

The length of the measure of YZ is 80cm

<h3>Perpendicular lines</h3>

Perpendicular lines are lines that are at angle 90 degrees to each other. From the given diagram;

WX = 82cm

Required

Length. of YZ

Using the pythagoras theorem

YV = VZ = √41²-9²

YV = VZ = √1600

YV = VZ = 40

Since YZ = YV + VZ

YZ = 40cm + 40cm

YZ= 80cm

Hence the length of the measure of YZ is 80cm

Learn more on perpendicular lines here: brainly.com/question/1202004

#SPJ1

5 0
2 years ago
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