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2 years ago

Independent Practice

Mathematics

1 answer:

Oduvanchick [21]2 years ago

8 0

I believe the answer is d y=x^3 i hope this helped

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If you have 3 quarters, 5 dimes, and 2 nickels in

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Answer:

Step-by-step explanation:

No. Of quarters n(Q)= 3

No. Of dimes n(D) = 5

No. Of nickels n(N) = 2

Total T = 3+5+2 = 10

Prob(D) = n(D)/T = 5/10 = 1/2

Now there are 9 left since it is not replaced back

Prob(Q) = 3/9 = 1/3

Prob(D and Q) = 1/2 × 1/3 = 1/6

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Step-by-step explanation:

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a television program is 60 minutes long, and 20% of the time is taken up by commercials. How many minutes of commercials are the

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There would be 12 minutes of commercials

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2 years ago

Solve 3[-x+(2x+1)]=x-1

12345 [234]

Answer:

x = 1

Step-by-step explanation:

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2 years ago

Jim is trying to improve his speed on the track so he can qualify for the State Championships. As he is running, he goes from 70

kumpel [21]

Answer:

His acceleration is $\frac{1}{15}$ meters per seconds²

Step-by-step explanation:

Acceleration is the rate of change of the speed

The formula of acceleration is $a=\frac{v_{f}-v_{i}}{t}$ , where

$v_{f}$ is the final speed
$v_{i}$ is the initial speed
The unit of the acceleration is meters/second²

∵ Jim goes from 70 meters/minute (beginning speed) to

106 meters/minute (final speed) in 9 seconds

∴ His initial speed $v_{i}$ = 70 meters/minute

- Change it the meter per second

∵ 1 minute = 60 seconds

∴ $\frac{70}{(1)(60)}=\frac{70}{60}=\frac{7}{6}$ meters/second

∴ $v_{i}$ = $\frac{7}{6}$ meters/second

∵ His final speed $v_{f}$ = 106 meters/minute

- Change it the meter per second

∴ $\frac{106}{(1)(60)}=\frac{106}{60}=\frac{53}{30}$ meters/second

∴ $v_{f}$ = $\frac{53}{30}$ meters/second

∵ The time of the change of his speed is 9 seconds

∴ t = 9

∵ The formula of acceleration is $a=\frac{v_{f}-v_{i}}{t}$

- Substitute the values of t, $v_{i}$ and $v_{f}$ in the formula above

∴ $a=\frac{\frac{53}{30}-\frac{7}{6}}{9}=\frac{1}{15}$

∴ His acceleration is $\frac{1}{15}$ meters per seconds²

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2 years ago