It has three lines of symmetry.
Add, then subtract and that’s your answer!
Answer:The roots of any quadratic equation is given by: x = [-b +/- sqrt(-b^2 - 4ac)]/2a. Write down the quadratic in the form of ax^2 + bx + c = 0. If the equation is in the form y = ax^2 + bx +c, simply replace the y with 0. This is done because the roots of the equation are the values where the y axis is equal to 0.
Step-by-step explanation:
13x + 5y = 16
2x - 8y = 20
Multiply the equations;
13x + 5y = 16 [x2]
2x - 8y = 20 [x13]
26x + 20y = 32
26x - 104y = 260
Reverse the signs on one equation;
26x + 20y = 32
-26x + 104y = -260
'-26x' gets cancelled, leaving;
20y = 32
104y = -260
20y + 104y = 124y
32 - 260 = -228
124y = -228
y = -228 / 124
y = -1.84
Substitute in one equation and find 'x'.
Hope this helped! :)
Answer:
Please explain better
Step-by-step explanation:
