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azamat
3 years ago
8

Does anyone know the answer to this I'm k12 btw​

Mathematics
2 answers:
VMariaS [17]3 years ago
7 0
2nd and 4th are the answers
kirill115 [55]3 years ago
7 0
The Second one and the fourth one
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mariarad [96]
Y=14.5
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allochka39001 [22]

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Step-by-step explanation:

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2 years ago
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Vladimir79 [104]
The correct answer is 400.
8 0
3 years ago
On a particular production line, the likelihood that a light bulb is defective is 10%. seven light bulbs are randomly selected.
amid [387]

Answer:

0.9995

Step-by-step explanation:

10% = 0.10

1 - 0.10 = 0.9

n = number of light bulbs = 7

we calculate this using binomial distribution.

p(x) = nCx × p^x(1-p)^n-x

our question says at most 4 is defective

= (7C0 × 0.1⁰ × 0.9⁷) + (7C1 × 0.1¹ × 0.9⁶) + (7C2 × 0.1² × 0.9⁵) + (7C3 × 0.1³ × 0.9⁴) + (7C4 × 0.1⁴ × 0.9³)

= 0.478 + 0.372 + 0.1239 + 0.023 + 0.0026

= 0.9995

we have 0.9995 probability that at most 4 light bulbs are defective.

6 0
3 years ago
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